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Butoxors [25]
4 years ago
12

Suppose that the variables grade1, grade2, and grade3 are declared as follows:

Computers and Technology
2 answers:
wel4 years ago
6 0

Answer:

Option B (grade1 + grade2 + grade3) / 3.0

Explanation:

The most accurate result is calculated by the expression given in the option B.  This is because all the <em>grade1</em>, <em>grade2</em> and <em>grade3</em> variables are integer type and therefore we need to add a decimal point after divisor (e.g. 3.0) so that the decimal points of the result can be preserved.

For example:

(88 + 92 + 83) / 3.0  should result in 87.66666666666667

If we do  (88 + 92 + 83) / 3, the decimal points are truncated to 87.

The expression in option c, (double)((grade1 + grade2 + grade3) / 3), will result in 87 as the  (grade1 + grade2 + grade3) / 3 will be evaluated first prior to converting into double type.

The expression in option d and e are inaccurate as they don't calculate average of the three variables.  

Mnenie [13.5K]4 years ago
5 0
A; you have to add the grades to have the total and then divide by 3 because there are 3 variables. 
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  2. def standard_deviation(aList):
  3.    sum = 0
  4.    for x in aList:
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  6.    
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Firstly, we need to import math module (Line 1).

Next, create a function standard_deviation that takes one input parameter, which is a list (Line 3). In the function, calculate the mean for the value in the input list (Line 4-8). Next, use the mean to calculate the variance (Line 10-15). Next, use sqrt method from math module to get the square root of variance and this will result in standard deviation (Line 16). At last, return the standard deviation (Line 18).

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