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2 years ago

Please help asap 25 pts

Mathematics

2 answers:

hjlf2 years ago

5 0

Correct anser is c just let me kno if you need more answers

OLEGan [10]2 years ago

3 0

Step 1. Subtract 3 from both sides

2|7x - 4| = 51 - 3

Step 2. Simplify 51 - 3 to 48

2|7x - 4| = 48

Step 3. Divide both sides by 2

|7x - 4| = 48/2

Step 4. Simplify 48/2 to 24

|7x - 4| = 24

Step 5 Break down the problem into these 2 equations

7x - 4 = 24

-(7x - 4) = 24

Step 6. Solve the 1st equation: 7x - 4 = 24

x = 4

Step 7. Solve the 2nd equation: -(7x - 4) = 24

x = -20/7

Step 8. Collect all solutions

x = -20/7,4

The answer is C.

You might be interested in

Describe the behavior of the function ppp around its vertical asymptote at x=-2x=−2x, equals, minus, 2.

insens350 [35]

Answer:

$x->-2^{-}, p(x)->-\infty$ and as $x->-2^{+}, p(x)->-\infty$

Step-by-step explanation:

Given

$p(x) = \frac{x^2-2x-3}{x+2}$ -- Missing from the question

Required

The behavior of the function around its vertical asymptote at $x = -2$

$p(x) = \frac{x^2-2x-3}{x+2}$

Expand the numerator

$p(x) = \frac{x^2 + x -3x - 3}{x+2}$

Factorize

$p(x) = \frac{x(x + 1) -3(x + 1)}{x+2}$

Factor out x + 1

$p(x) = \frac{(x -3)(x + 1)}{x+2}$

We test the function using values close to -2 (one value will be less than -2 while the other will be greater than -2)

We are only interested in the sign of the result

----------------------------------------------------------------------------------------------------------

As x approaches -2 implies that:

$x -> -2^{-}$ Say x = -3

$p(x) = \frac{(x -3)(x + 1)}{x+2}$

$p(-3) = \frac{(-3-3)(-3+1)}{-3+2} = \frac{-6 * -2}{-1} = \frac{+12}{-1} = -12$

We have a negative value (-12); This will be called negative infinity

This implies that as x approaches -2, p(x) approaches negative infinity

$x->-2^{-}, p(x)->-\infty$

Take note of the superscript of 2 (this implies that, we approach 2 from a value less than 2)

As x leaves -2 implies that: $x>-2$

Say x = -2.1

$p(-2.1) = \frac{(-2.1-3)(-2.1+1)}{-2.1+2} = \frac{-5.1 * -1.1}{-0.1} = \frac{+5.61}{-0.1} = -56.1$

We have a negative value (-56.1); This will be called negative infinity

This implies that as x leaves -2, p(x) approaches negative infinity

$x->-2^{+}, p(x)->-\infty$

So, the behavior is:

$x->-2^{-}, p(x)->-\infty$ and as $x->-2^{+}, p(x)->-\infty$

6 0

2 years ago

Right answer no lin or bot

kvv77 [185]

Answer:

$2\frac{9}{10} or\frac{29}{10}$

Step-by-step explanation:

Hope this helps! Have a great day ahead. Happy halloween :) Stay Safe <33

8 0

2 years ago

Read 2 more answers

Find the distance between each set of points. Round to the nearest tenth, when necessary. (-3, 2) and (1, -6)

vovangra [49]

Answer:

<h2>The answer is 8.9 units</h2>

Step-by-step explanation:

The distance between two points can be found by using the formula

$d = \sqrt{ ({x1 - x2})^{2} + ({y1 - y2})^{2} } \\$

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(-3, 2) and (1, -6)

The distance between them is

$d = \sqrt{ ({ - 3 - 1})^{2} + ({2 + 6})^{2} } \\ = \sqrt{ ({ - 4})^{2} + {8}^{2} } \\ = \sqrt{16 + 64} \\ = \sqrt{80} \: \: \: \: \: \: \: \: \: \: \\ = 4 \sqrt{5} \: \: \: \: \: \: \: \: \: \: \\ = 8.9442719...$

We have the final answer as

8.9 units to the nearest tenth

Hope this helps you

6 0

2 years ago

What’s the value of a ?

otez555 [7]

The answer is (B)16.

4 0

2 years ago

Is my answer correct or no? <br> ---> show explanation & details if i am wrong!!!

neonofarm [45]

Answer:

No, because the distance from the origin to point (7 , -7) is greater than the radius of the circle ⇒ 3rd answer

Step-by-step explanation:

From the graph of the circle

∵ The center of the circle F is at the origin

∴ F is (0 , 0)

∵ The circle passes through point (7 , 0)

- The length of the radius of the circle is the distance between

the center of the circle and a point on the circle

∴ r is the distance between points (0 , 0) and (7 , 0)

∴ $r=\sqrt{(7-0)^{2}+(0-0)^{2}}=\sqrt{49}=7$

∴ The length of the radius of the circle is 7 units

Let us find the distance between point (7 , -7) and the origin (0 , 0)

If the distance is equal to the radius of the circle, then the point is on the circle
If the distance is greater than the radius, then the point is outside the circle
If the distance is less than the radius, then the point is inside the circle

∵ The distance = $\sqrt{(7-0)^{2}+(-7-0)^{2}}=\sqrt{49+49}=\sqrt{98}=7\sqrt{2}$

∵ r = 7

∵ $7\sqrt{2}$ > 7

∴ The distance is greater than the radius of the circle

∴ Point (7 , -7) lies outside the circle

The correct answer is:

No, because the distance from the origin to point (7 , -7) is greater than the radius of the circle

<em>Your answer is not correct, the correct answer is the 3rd answer</em>

3 0

2 years ago