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Anna11 [10]
3 years ago
6

The heights (in inches) of the starting players on a high school basketball team are as follows: 72, 75, 78, 72, 73. how many pl

ayers are there?
Mathematics
1 answer:
Alex_Xolod [135]3 years ago
7 0
The answer is:  " 5 (five) players " .
____________________________________________________
        (Note:  We are given FIVE (5) values in the data set).
_____________________________________________________
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How can you make a g o ogle m e e t without being warned
Marina86 [1]

Answer:

what do you mean being warned? just make it normally

Step-by-step explanation:

8 0
3 years ago
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A cylindrical pressure has a height of 9 feet and diameter of 6 feet. How much gas can the pressure vessel hold when full?
AleksAgata [21]

Answer:

81π ft³

Step-by-step explanation:

If the diameter is 6 ft, the radius is 3 ft.  

The volume is V = (area of base)(height).

Here,                V = (π[3 ft]²)(9 ft) = 81π ft³

3 0
3 years ago
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How do I solve out 5x188
mihalych1998 [28]

Answer:

940

Step-by-step explanation:

 188

<u>×    5</u>

 940

--------------------------------------------------------

8 * 5 = 40

Carry the 4 to the next 8

8 * 5 = 40

Add the 4 to the 40

40 + 4 = 48

Carry the 4 to the 1

1 * 5 = 5

Add the 4

5 + 9

= 940

*Hope this helps .^.*

5 0
3 years ago
The life of a red bulb used in a traffic signal can be modeled using an exponential distribution with an average life of 24 mont
BartSMP [9]

Answer:

See steps below

Step-by-step explanation:

Let X be the random variable that measures the lifespan of a bulb.

If the random variable X is exponentially distributed and X has an average value of 24 month, then its probability density function is

\bf f(x)=\frac{1}{24}e^{-x/24}\;(x\geq 0)

and its cumulative distribution function (CDF) is

\bf P(X\leq t)=\int_{0}^{t} f(x)dx=1-e^{-t/24}

• What is probability that the red bulb will need to be replaced at the first inspection?

The probability that the bulb fails the first year is

\bf P(X\leq 12)=1-e^{-12/24}=1-e^{-0.5}=0.39347

• If the bulb is in good condition at the end of 18 months, what is the probability that the bulb will be in good condition at the end of 24 months?

Let A and B be the events,

A = “The bulb will last at least 24 months”

B = “The bulb will last at least 18 months”

We want to find P(A | B).

By definition P(A | B) = P(A∩B)P(B)

but B⊂A, so  A∩B = B and  

\bf P(A | B) = P(B)P(B) = (P(B))^2

We have  

\bf P(B)=P(X>18)=1-P(X\leq 18)=1-(1-e^{-18/24})=e^{-3/4}=0.47237

hence,

\bf P(A | B)=(P(B))^2=(0.47237)^2=0.22313

• If the signal has six red bulbs, what is the probability that at least one of them needs replacement at the first inspection? Assume distribution of lifetime of each bulb is independent

If the distribution of lifetime of each bulb is independent, then we have here a binomial distribution of six trials with probability of “success” (one bulb needs replacement at the first inspection) p = 0.39347

Now the probability that exactly k bulbs need replacement is

\bf \binom{6}{k}(0.39347)^k(1-0.39347)^{6-k}

<em>Probability that at least one of them needs replacement at the first inspection = 1- probability that none of them needs replacement at the first inspection. </em>

This means that,

<em>Probability that at least one of them needs replacement at the first inspection =  </em>

\bf 1-\binom{6}{0}(0.39347)^0(1-0.39347)^{6}=1-(0.60653)^6=0.95021

5 0
3 years ago
Use the figure to find measures of the numbered angles.
Dafna1 [17]

Answer:

1 = 137

2 = 43

3 = 43

4 = 137

Step-by-step explanation:

for the first line, do (180-137 = 43)

then, 43 would be corresponding angle to 2 - making them equal

2 would be vertically opposite to 3, making them equal

137 and 1 are corresponding- making them equal

4 is vertically opposite to 1 - making them equal

8 0
3 years ago
Read 2 more answers
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