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Oxana [17]
3 years ago
9

A SCUBA diver with a 4-liter lung capacity is at a depth of 135 feet (4 atm.) She ascends to the surface where the

Chemistry
2 answers:
Nostrana [21]3 years ago
5 0

Answer:

16L

Explanation:

Data obtained from the question include:

V1 (initial volume) = 4L

P1 (initial pressure) = 4atm

P2 (final pressure) = 1atm

V2 (final volume) =?

Using Boyle's law equation P1V1 = P2V2, the new volume can be obtain as follow:

P1V1 = P2V2

4 x 4 = 1 x V2

16 = V2

V2 = 16L

Therefore, her new lungs volume is 16L

anastassius [24]3 years ago
3 0

Answer:

the volume decreases, 16 Li hope i helped you good day and God bless!

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List the following types of electromagnetic radiation in order of increasing wavelength.
chubhunter [2.5K]

Answer:

Radio, Microwave, Infared, Ultraviolet

Explanation:

look at the EM spectrum

3 0
3 years ago
If potassium (K) has a density of 0.86 g/cm3, which element would have a similar density?
Nata [24]

Answer:

C: Sodium

Explanation:

Iron had a way higher density neon has way to know as well as carbon and the closest one is sodium

4 0
3 years ago
Read 2 more answers
In the Haber process for ammonia synthesis, K " 0.036 for N 2 (g) ! 3 H 2 (g) ∆ 2 NH 3 (g) at 500. K. If a 2.0-L reactor is char
lisabon 2012 [21]

Answer : The partial pressure of N_2,H_2\text{ and }NH_3 at equilibrium are, 1.133, 2.009, 0.574 bar respectively. The total pressure at equilibrium is, 3.716 bar

Solution :  Given,

Initial pressure of N_2 = 1.42 bar

Initial pressure of H_2 = 2.87 bar

K_p = 0.036

The given equilibrium reaction is,

                              N_2(g)+H_2(g)\rightleftharpoons 2NH_3(g)

Initially                   1.42      2.87             0

At equilibrium    (1.42-x)  (2.87-3x)     2x

The expression of K_p will be,

K_p=\frac{(p_{NH_3})^2}{(p_{N_2})(p_{H_2})^3}

Now put all the values of partial pressure, we get

0.036=\frac{(2x)^2}{(1.42-x)\times (2.87-3x)^3}

By solving the term x, we get

x=0.287\text{ and }3.889

From the values of 'x' we conclude that, x = 3.889 can not more than initial partial pressures. So, the value of 'x' which is equal to 3.889 is not consider.

Thus, the partial pressure of NH_3 at equilibrium = 2x = 2 × 0.287 = 0.574 bar

The partial pressure of N_2 at equilibrium = (1.42-x) = (1.42-0.287) = 1.133 bar

The partial pressure of H_2 at equilibrium = (2.87-3x) = [2.87-3(0.287)] = 2.009 bar

The total pressure at equilibrium = Partial pressure of N_2 + Partial pressure of H_2 + Partial pressure of NH_3

The total pressure at equilibrium = 1.133 + 2.009 + 0.574 = 3.716 bar

6 0
3 years ago
If you set up an experiment with two different independent variables, then the results would be_____.
MariettaO [177]

Answer: A) Inconclusive; you would not know which of the two variables caused the change.

Explanation:

When you set up an experiment, you must make sure that you control the variables such that only one independent variable changes at a time, while all the remainder conditions (the other independent variables) are controlled (fixed).

By observing (measuring) the dependent variable, while only one independent variable changes you can understandhow such independent variable explains (determines) the dependent variable, leading to a conclusion.

Conversely, if two or more independent variables change at a time, then there is no way that you can tell how the output (dependent variable) is related with one or other of the changes of the indipendent variables. You wolud not be able to discriminate (distinguish) the effect of one or other variable, making the experiment inconclusive

I really hope this answer helps you out! It makes my day helping people like you and giving back to the community that has helped me through school! If you could do me a favor, if this helped you and this is the very best answer and you understand that all of my answers are legit and top notch. Please mark as brainliest! Thanks and have a awesome day!

4 0
3 years ago
An aqueous solution contains the following ions: cl−, ag , pb2 , no−3, and so2−4. More than one precipitate will form. Identify
klasskru [66]

An aqueous solution contains the following ions Cl⁻, Ag⁺, Pb²⁺, NO₃⁻ & SO₄²⁻ and more than one precipitate will form are AgCl, PbCl₂, PbSO₄ & Ag₂SO₄.

<h3>What is precipitate?</h3>

Precipitate is the insoluble compound which is present at the bottom of any chemical reaction in the solid state.

If in an aqueous solution Cl⁻, Ag⁺, Pb²⁺, NO₃⁻ & SO₄²⁻ ions are present then:

  • Compounds AgCl, PbCl₂, PbSO₄ & Ag₂SO₄ are not soluble in water as it is present in the form of precipitate.
  • Pb(NO₃)₂ is fully soluble in water and will not make precipitate.

Hence precipitates are AgCl, PbCl₂, PbSO₄ & Ag₂SO₄.

To know more about precipitates, visit the below link:

brainly.com/question/2437408

#SPJ4

8 0
2 years ago
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