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Oxana [17]
3 years ago
9

A SCUBA diver with a 4-liter lung capacity is at a depth of 135 feet (4 atm.) She ascends to the surface where the

Chemistry
2 answers:
Nostrana [21]3 years ago
5 0

Answer:

16L

Explanation:

Data obtained from the question include:

V1 (initial volume) = 4L

P1 (initial pressure) = 4atm

P2 (final pressure) = 1atm

V2 (final volume) =?

Using Boyle's law equation P1V1 = P2V2, the new volume can be obtain as follow:

P1V1 = P2V2

4 x 4 = 1 x V2

16 = V2

V2 = 16L

Therefore, her new lungs volume is 16L

anastassius [24]3 years ago
3 0

Answer:

the volume decreases, 16 Li hope i helped you good day and God bless!

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Explanation:

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b. 3d, d is l = 2 then 2 x 2 + 1 = 5 sublevels, 5*2=10 electrons in the d subshell

c. 4s, s is l=0 then 2 x 0 + 1 = 1 sublevel, 1*2=2 electrons in the s subshell.

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Minchanka [31]
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