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Vinvika [58]
3 years ago
8

8.03 Solutions Lab Report Does anyone have a PDF or Document of FLVS 8.03 Solutions Lab

Chemistry
2 answers:
GarryVolchara [31]3 years ago
7 0

8.03 solutions report is described below.

Explanation:

8.03 Solutions Lab Report

In this laboratory activity, you will investigate how temperature, agitation, particle size, and dilution affect the taste of a drink. Fill in each section of this lab report and submit it and your pre-lab answers to your instructor for grading.  

Pre-lab Questions:

In this lab, you will make fruit drinks with powdered drink mix. Complete the pre-lab questions to get the values you need for your drink solutions.  

Calculate the molar mass of powered fruit drink mix, made from sucrose (C12H22O11).

Using stoichiometry, determine the mass of powdered drink mix needed to make a 1.0 M solution of 100 mL.

-BARSIC- [3]3 years ago
5 0

Answer:

I need it too.

Explanation:

Did you ever do it?

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During which change of state do atoms lose energy? (FIRST TO ANSWER WITH RIGHT ANSWER GETS BRAILEST)
andreyandreev [35.5K]

Answer:

When the atoms are freezing, they lose energy.

I hope this helped at all.

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The product of adding two molecules of an alcohol to an aldehyde in the presence of acid is a(n):______
Anna35 [415]

Answer:

A

Explanation:

Acetals are geminal-diether derivatives of aldehydes or ketones, formed by reaction with two equivalents (or an excess amount) of an alcohol and elimination of water. Ketone derivatives of this kind were once called ketals, but modern usage has dropped that term.

To achieve effective hemiacetal or acetal formation, two additional features must be implemented. First, an acid catalyst must be used because alcohol is a weak nucleophile and second the water produced with the acetal must be removed from the reaction.

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3 years ago
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As a substance changes fees from gas to liquid to solid :
Korolek [52]

I would say that the density increases because the distance between the molecules decreases, and therefore becomes smaller, and vice versa the density increases, and that is a physical change not a chemical change.

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3 years ago
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Carbonic anhydrase of erythrocytes (Mr 30,000) has one of the highest turnover numbers known. It catalyzes the reversible hydrat
Afina-wow [57]

Explanation:

According to the given data, the turnover number can be calculated as follows.

      Turnover number = K_{cat} = \frac{V_{max}}{\text{Concentration of enzyme}}

     V_{max} = \frac{\text{Moles of CO_{2} hydrolyzed}{second}

Therefore, moles of CO_{2} hydrolyzed is as follows.

Moles of CO_{2} hydrolyzed = \frac{Mass of CO_{2}}{Molar mass of CO_{2}}

                 = \frac{0.30}{44}

                 = 0.00682 moles

Now, moles of CO_{2} hydolyzed per second is calculated as follows.

Moles of CO_{2} hydolyzed per second = \frac{0.00682}{60}

             = 1.137 \times 10^{-4} moles/second = V_{max}

And,

Moles of enzyme = \frac{Mass}{\text{Molar mass}}

                       = \frac{10.0 \mu g}{30000}

                       = 3.33 \times 10^{-10} moles

Therefore, the value of K_{cat} is as follows.

    K_{cat} = \frac{1.137 \times 10^{-4} moles}{3.333 \times 10^{-10} moles}

               = 0.3411 \times 10^{6} per second

               = 0.3411 \times 60 \times 10^{6} per minute

               = 20.466 \times 10^{6} per minute

Thus, we can conclude that the turnover number (K_{cat}) of carbonic anhydrase (in units of min^{-1}) is 20.466 \times 10^{6} per minute.

6 0
3 years ago
When HCl is added to water, the [H3O+] = 0.6 M. What is the [OH-]?
makkiz [27]

Answer:

The answer is

<h2>[OH-] = 1.66 × 10^-14 M</h2>

Explanation:

To find the [OH-] we must first find the pH and the pOH of the solution

That's

pH + pOH = 14

pOH = 14 - pH

To find the pH we use the formula

pH = -log [H3O+]

From the question

[H3O+] = 0.6 M

pH = - log 0.6

pH = 0.22

pOH = 14 - 0.22

pOH = 13.78

We can now find the [OH -] in the solution using the formula

pOH = - log [OH-]

13.78 = - log [OH-]

Find the antilog of both sides

We have the final answer as

<h3>[OH-] = 1.66 × 10^-14 M</h3>

Hope this helps you

3 0
3 years ago
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