The solubility of lead (ii) chloride (pbcl2) is 1.6 ⋅ 10-2 m. what is the ksp of pbcl2? the solubility of lead (ii) chloride (pb
cl2) is 1.6 10-2 m. what is the ksp of pbcl2? 3.1 ⋅ 10-7 5.0 ⋅ 10-4 1.6 ⋅ 10-5 1.6 ⋅ 10-2 4.1 ⋅ 10-6
2 answers:
According to the equilibrium equation for this reaction:
PbCl2(s) ↔ Pb2+(aq) + 2Cl-(aq)
So when Ksp is the solubility product constant for a solid substance when it
dissolved in the solution. and measure how a solute dissolves in the solution
So, Ksp expression = [Pb2+] [Cl-]^2
and when the solubility is the maximum quantity of solute which can dissolve in a certain solute.
So, we assume the solubility = X
∴[Pb2+] = X = 1.6 x 10^-2 M
[Cl-] = 2X = 2 * 1.6 x 10^-2 = 0.032 M
by substitution:
∴ Ksp = (1.6 x 10^-2) * (0.032)^2
= 1.64 x 10^-5
Answer:The Solubility product of
is
.
Explanation;
Solubility of 

S 2S
The expression of
is given as:


The Solubility product of
is
.
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