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nignag [31]
3 years ago
14

Why is salt put on icy roads and sidewalks in the winter?

Chemistry
1 answer:
balandron [24]3 years ago
3 0
So that ice would not melts and it helps to keep grip for walking or driving
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What is the correct answer? Please
Vikki [24]

Answer:

Latitude

ocean currents

Wind

Elevation

Water

3 0
3 years ago
What kind of waves can travel through a vacuum?
enyata [817]

Answer:

electromagnetic wave

Explanation:

Electromagnetic waves differ from mechanical waves in that they do not require a medium to propagate.

8 0
3 years ago
Which coefficient should appear in front of LiNO3 in the balanced equation?
ikadub [295]
Missing chemical reaction:
Pb(NO₃)₂(aq) + Li₂SO₄(aq) → PbSO₄(s) + LiNO₃(aq).
Answer is:
Balanced chemical reaction:
Pb(NO₃)₂(aq) + Li₂SO₄(aq) → PbSO₄(s) + 2LiNO₃(aq).
Number of atoms on both side of chemical reaction must be the same. There is two lithium atoms, two nitrogs, ten oxygen atoms, one lead and one sulfur on both side of balanced chemical reaction.
4 0
4 years ago
Negative radical in the periodic table​
yKpoI14uk [10]

Answer:

A radical is a group of atoms of elements carrying a charge, e.g., chlorate [ClO3–]. Radicals or ions are formed by losing or gaining electrons. When an electron is gained the group of atoms acquire a negative charge and is called a negative radical or negative ion.

5 0
3 years ago
How much heat is required to change 100 g of ice (H2O) at 253 K to vapor (steam) at 393 K?
soldier1979 [14.2K]

<u>Answer:</u> The heat required will be 58.604 kJ.

<u>Explanation: </u>

To calculate the amount of heat required, we use the formula:

Q= m\times c\times \Delta T

Q= heat gained  or absorbed = ? J

m = mass of the substance = 100 g

c = heat capacity of water = 4.186 J/g ° C

Putting values in above equation, we get:

\Delta T={\text{Change in temperature}}=(393-253)K=140K=140^oC

Q=100g\times 4.186J/g^oC\times 140^oC

Q = 58604 Joules  = 58.604 kJ     (Conversion factor: 1 kJ = 1000J)

Thus, heat released by 100 grams of ice is 58.604kJ.

3 0
4 years ago
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