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Vesna [10]
3 years ago
7

Using the following equation, find the center and radius of the circle. You must show all work and calculations to receive credi

t.
x ²+ 4x + y ²− 6y = −4
Mathematics
1 answer:
In-s [12.5K]3 years ago
4 0
Get into form
(x-h)²+(y-k)²=r²
center is (h,k) and radius is r

complete the square for each
(x²+4x)+(y²-6y)=-4
take 1/2 of each linear coefienet and square it
4/2=2, 2²=4
-6/2=-3, (-3)²=9
add that to both sides
(x²+4x)+4+(y²-6y)+9=-4+4+9
(x²+4x+4)+(y²-6y+9)=9
complete the squares
(x+2)²+(y-3)²=3²
(x-(-2))²+(y-3)²=3²

the center is (-2,3) and radius is 3
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First, let (x,y) be a point in our parabola. Since we know that the focus of our parabola is  the point (0,8), we are going to use the distance formula to find the distance between the two points:
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Next, we are going to find the distance between the directrix and the point in our parabola. Remember that the distance between a point (x,y) of a parabola and its directrix, y=c, is: |y-c|. Since our directrix is y=-8, the distance to our point will be:
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Now, we are going to equate those two distances, and square them to get rid of the square root and the absolute value:
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Finally, we can expand and solve for y:
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y= \frac{1}{32} x^2

We can conclude that t<span>he standard form of the equation of the parabola with a focus at (0, 8) and a directrix at y = -8 is </span>y= \frac{1}{32} x^{2}

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