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11Alexandr11 [23.1K]
3 years ago
9

4. A discus is thrown from a height of 4 feet with an initial velocity of 65 ft/s at an angle of 44° with the horizontal. How lo

ng will it take for the discus to reach the ground?

Mathematics
2 answers:
joja [24]3 years ago
7 0

I believe the time would be about 4 seconds

Monica [59]3 years ago
6 0

Answer:

9.29 seconds

Step-by-step explanation:

Attached is my work because it's difficult to type

Attached is an image of where I got my equations from

the answer may be wrong

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7*9=(7*10)-7*A) what is the value of A
Aliun [14]
7*9=(7*10)-7*a
    63 = 70-7a
   -70    -70
-7=-7a
-7/-7 =1
1=a
7 0
4 years ago
Four hundred randomly selected working adults in a certain state, including those who worked at home, were asked the distance fr
Drupady [299]

Answer:

The 99% confidence interval for the mean distance from home to work for all residents of this state is between 8.49 and 9.19 miles.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.99}{2} = 0.005

Now, we have to find z in the Z-table as such z has a p-value of 1 - \alpha.

That is z with a pvalue of 1 - 0.005 = 0.995, so Z = 2.575.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 2.575\frac{2.7}{\sqrt{400}} = 0.35

The lower end of the interval is the sample mean subtracted by M. So it is 8.84 - 0.35 = 8.49 miles.

The upper end of the interval is the sample mean added to M. So it is 8.84 + 0.35 = 9.19 miles.

The 99% confidence interval for the mean distance from home to work for all residents of this state is between 8.49 and 9.19 miles.

3 0
3 years ago
A pilot flew a jet from City A to City B, a distance of 2300 mi. On the return trip, the average speed was 20% faster than the o
Ugo [173]

The speed from City A to City B is 506 miles per hour

<em><u>Solution:</u></em>

A pilot flew a jet from City A to City B, a distance of 2300 miles

Distance for trip = 2300 miles

Distance for return trip = 2300 miles

The round-trip took 8 h 20 min

Total time taken for both trips = 8 hour 20 minutes

We know that,

1 hour = 60 minutes

20 \text{ minutes } = \frac{20}{60} \text{ hour } =\frac{1}{3} \text{ hour }

Thus, we get,

Total time taken for both trips = 8 + \frac{1}{3} = \frac{24+1}{3} = \frac{25}{3} \text{ hour }

On the return trip, the average speed was 20% faster than the outbound speed

Let "x" be the speed for out bound trip

Then, x + 20 % of x is the average speed of return trip

x + 20\% x = x + 0.2x = 1.2x

Speed for return trip = 1.2x

<em><u>Time taken is given by formula:</u></em>

\text{total time } = \frac{distance}{\text{speed of outbound trip}} + \frac{distance}{\text{speed of return trip}}

\frac{25}{3} = \frac{2300}{x} + \frac{2300}{1.2x}\\\\\frac{25x}{3} = \frac{2300 \times 1.2 + 2300}{1.2}\\\\10x = 5060\\\\x = 506

Thus speed from City A to City B is 506 miles per hour

4 0
4 years ago
I need help does any one knows the answer?​
PolarNik [594]

Answer:

-5

Step-by-step explanation:

ur welcome!

6 0
3 years ago
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Graph g(x) = 3x2 - 2. Compare the graph to f(x) = x2
andre [41]
I think the answer is a
3 0
3 years ago
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