Answer:
1.7 × 10⁻⁴
Step-by-step explanation:
The question relates to a two sample z-test for the comparison between the means of the two samples
The null hypothesis is H₀: μ₁ ≤ μ₂
The alternative hypothesis is Hₐ: μ₁ > μ₂

Where;
= 13.5
= 12
σ₁ = 2.5
σ₂ = 1.5
We set our α level at 0.05
Therefore, our critical z = ± 1.96
For n₁ = n₂ = 23, we have;

We reject the null hypothesis at α = 0.05, as our z-value, 3.5969 is larger than the critical z, 1.96 or mathematically, since 3.5969 > 1.96
Therefore, there is enough statistical evidence to suggest that Alyse time is larger than Jocelyn in a 1 mile race on a randomly select day and the probability that Alyse has a larger time than Jocelyn is 0.99983
Therefore;
The probability that Alyse has a smaller time than Jocelyn is 1 - 0.99983 = 0.00017 = 1.7 × 10⁻⁴.
Answer:
Explanation:
fg(x) = (x+2)(3x^2 - 1)
= 3x^3 - x + 6x^2 - 2
= 3x^3 + 6x^2 - x - 2
gf(x) = (3x^2 - 1)(x + 2)
= 3x^3 + 6x^2 - x - 2
As you can see:
fg(x) = gf(x)
3x^3 + 6x^2 - x - 2 = 3x^3 + 6x^2 - x - 2
Each person gets 1 1/4 bars.
You divide the 5 bars by 4 people: 5/4 = 1 1/4
For the answer to the question above, n the 1st month, the accrued interest is ___ (1/12) * .0525 * 135400
subtract the interest from the payment to find the change in the principal for the 2nd month
find the 2nd month's interest and subtract from the payment to find the amount applied to principal. Then that's it!