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Zepler [3.9K]
4 years ago
12

As an auto mechanic, you need to determine the emf and internal resistance of an old battery. you perform these two measurements

: (1) you apply a voltmeter to the battery\'s terminals and read 11.8 v. (2) an ammeter applied to the terminals indicates 16.5
a. what are the battery\'s emf and internal resistance?
Physics
1 answer:
stiks02 [169]4 years ago
3 0
We are asked to solve for the internal resistance of the electromotive battery and to answer this we need to apply Ohm's Law which is Voltage is equal to the product of measured current and resistance (V = IR). Thus, to solve for resistance we have it R = V/I where voltage was measured and value is equal to 11.8 volts and current was also measured and the value is 16.5 amperes.

Solving the internal resistance, we have it:
R = V/ I
R = 11.8 volts / 16.5 amperes
R = 0.715 ohms

The answer is 0.715 ohms.
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A force F acting on an object of mass m causes a displacement d. The angle between these two vectors is Θ. The work W done on th
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PLEASE HELP <3
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1) The landing spot of the projectile is given by d=v_x \sqrt{\frac{2h}{g}}

2) The common variable is the time

Explanation:

1)

The motion of a projectile consists of two independent motions:  

- A uniform motion (constant velocity) along the horizontal direction  

- A uniformly accelerated motion, with constant acceleration (acceleration of gravity) in the downward direction  

The landing spot can be determined in the following way:

- First of all, we analyze the vertical motion to find the time of flight of the projectile. This can be done by using the suvat equation

h=ut+\frac{1}{2}at^2

where

h is the vertical displacement of the projectile, which corresponds to the height from which the projectile has been fired, above the ground

u = 0 is the initial vertical velocity

a=g=9.8 m/s^2 is the acceleration of gravity

t is the time of flight

Solving for t,

t=\sqrt{\frac{2h}{g}}

- After finding the time of flight, we analyze the horizontal motion, which is a uniform motion with constant horizontal velocity v_x. Therefore, the horizontal distance covered is given by

d=v_x t

And substituting the time of flight,

d=v_x \sqrt{\frac{2h}{g}}

2)

Since the horizontal motion is uniform, the horizontal component of the displacement of the projectile is given by

x=v_x t

where v_x is the horizontal velocity and t is the time.

The vertical motion is accelerated, so the vertical component of the displacement is given by

y=\frac{1}{2}gt^2

where g is the acceleration of gravity and t is the time.

Therefore, from the two equations we see that the common variable is t, the time.

Learn more about projectile:

brainly.com/question/8751410

#LearnwithBrainly

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