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son4ous [18]
3 years ago
9

Malika is writing an essay about the Sun. Below is the first paragraph in the essay. The Sun is an average-size star that is loc

ated at the center of the solar system. This hot, glowing ball of gas has a diameter of 1,393,000 km. This means 109 Earths would fit side by side across the diameter of the Sun. At the surface, the Sun’s temperature is about 550 degrees Celsius. Earth is located just under 150 million kilometers from the Sun. Malika quickly realizes this paragraph contains an error. Which statement identifies the error? The Sun is a large star, not an average-size star. The Sun is not a glowing ball of gas—it is solid. The Sun’s surface temperature is about 5500 degrees Celsius. Earth is located over 300 million kilometers from the Sun.
Physics
2 answers:
joja [24]3 years ago
5 0

The answer would be:


<u>The Sun's surface temperature is about 5,500 degrees Celsius. </u>


The surface of the Sun is about 5,778 Kelvin. If you want to be exact the sun is 5,505 degrees Celsius and that's just the surface. The corona gets even hotter reaching about 10 million degrees Celsius. The other information about the Sun is correct.

harina [27]3 years ago
4 0

Answer: Option (c) is the correct answer.

Explanation:

Sun is a large star and as it is given that it's diameter is 1,393,000 km. Since there are nuclear reactions that take place inside the Sun, therefore, there is emission of lot of radiations.

As a result, lot of heat energy is there. So, the statement at the surface Sun’s temperature is about 550 degrees Celsius will be an error.

Thus, we can conclude that this error is identified by the statement the Sun’s surface temperature is about 5500 degrees Celsius.

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A car has uniform velocity of 108km/hour. How far does it travel in 1 1/2 minutes
Nostrana [21]

Answer:

2.7km

Explanation:

Two methods: Convert km/hour to km/minutes or convert 3/2 minutes to hours.

Then multiply time to get the distance of the car traveled.

3 0
2 years ago
The particle, initially at rest, is acted upon only by the electric force and moves from point a to point b along the x axis, in
bezimeni [28]

1) Potential difference: 1 V

2) V_b-V_a = -1 V

Explanation:

1)

When a charge moves in an electric field, its electric potential energy is entirely converted into kinetic energy; this change in electric potential energy is given by

\Delta U=q\Delta V

where

q is the charge's magnitude

\Delta V is the potential difference between the initial and final position

In this problem, we have:

q=4.80\cdot 10^{-19}Cis the magnitude of the charge

\Delta U = 4.80\cdot 10^{-19}J is the change in kinetic energy of the particle

Therefore, the potential difference (in magnitude) is

\Delta V=\frac{\Delta U}{q}=\frac{4.80\cdot 10^{-19}}{4.80\cdot 10^{-19}}=1 V

2)

Here we have to evaluate the direction of motion of the particle.

We have the following informations:

- The electric potential increases in the +x direction

- The particle is positively charged and moves from point a to b

Since the particle is positively charged, it means that it is moving from higher potential to lower potential (because a positive charge follows the direction of the electric field, so it moves away from the source of the field)

This means that the final position b of the charge is at lower potential than the initial position a; therefore, the potential difference must be negative:

V_b-V_a = - 1V

8 0
2 years ago
A 1500 kg car, initially traveling at 22.0 m/s, hits its brakes and skids to a stop. Determine the work done by friction.
Sedbober [7]

Answer:

<em>The work done by the car is 363 kJ</em>

Explanation:

Work : Work is said to be done when a Force moves an object through a certain distance. Work and Energy are interchangeable because they have the same unit. The unit of work is Joules (J).

Mathematically work done can be expressed as,

E = W = 1/2mv²

W =  1/2mv²................................ Equation 1

Where E = Energy, W = work done, m = mass of the car, v = velocity of the car

<em>Given: m=1500 kg, v=22 m/s</em>

<em>Substituting these values into equation 1</em>

<em>W = 1/2(1500)(22)²</em>

<em>W = 750 × 484</em>

<em>W = 363000 J</em>

<em>W = 363 kJ</em>

<em>Thus the work done by the car is 363 kJ</em>

8 0
3 years ago
As the mass of an object increases, the weight of the object will ______?
Sergio039 [100]

Answer:

also increase

Explanation:

If the mass increases so will the weight.

4 0
2 years ago
A backyard swimming pool with a circular base of diameter 6.00m is filled to depth 1.50m. (b) Two persons with combined mass 150
Mashutka [201]

The pressure increase at the bottom of the pool after they enter the pool and float is 106.103 Pa.

<h3>What is absolute pressure?</h3>

Absolute pressure is the force that exists in a space when there is no matter present, or when there is a perfect vacuum. This absolute zero serves as the baseline for measurements in absolute pressure. The measurement of barometric pressure is the greatest illustration of an absolute referenced pressure. In order to determine absolute pressure, a complete vacuum is used. In contrast, gauge pressure is the amount of pressure that is measured in relation to atmospheric pressure, also referred to as barometric pressure.

given,

diameter = 6 m

depth = h = 1.5 m

Atmospheric pressure = P₀ = 10⁵ Pa

a) absolute pressure

P = P₀ + ρ g h

P = 10⁵ + 1000 x 10 x 1.5

P = 1.15 x 10⁵ Pa

b) When two person enters into the pool,

mass of the two person = 150 Kg

weight of water level displaced exists equal to the weight of person.

\rho \mathrm{Vg}=2 \mathrm{mg} \\

V=\frac{2 m}{\rho} \\

V=\frac{2 \times 150}{1000} \\

\mathrm{~V}=0.3 \mathrm{~m}^3

Area of pool $=\frac{\pi}{4} d^2$

&=\frac{\pi}{4} \times 6^2 \\

&=28.27 \mathrm{~m}^2

Height of the water rise

h &=\frac{V}{A} \\

h &=\frac{0.3}{28.27} \\

& \mathrm{~h}=0.0106 \mathrm{~m}

  • Pressure increased

P = ρ g h

P = 1000 x 10 x 0.0106

P = 106.103 Pa

To learn more about absolute pressure refer to:

brainly.com/question/17200230

#SPJ4

4 0
1 year ago
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