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son4ous [18]
3 years ago
9

Malika is writing an essay about the Sun. Below is the first paragraph in the essay. The Sun is an average-size star that is loc

ated at the center of the solar system. This hot, glowing ball of gas has a diameter of 1,393,000 km. This means 109 Earths would fit side by side across the diameter of the Sun. At the surface, the Sun’s temperature is about 550 degrees Celsius. Earth is located just under 150 million kilometers from the Sun. Malika quickly realizes this paragraph contains an error. Which statement identifies the error? The Sun is a large star, not an average-size star. The Sun is not a glowing ball of gas—it is solid. The Sun’s surface temperature is about 5500 degrees Celsius. Earth is located over 300 million kilometers from the Sun.
Physics
2 answers:
joja [24]3 years ago
5 0

The answer would be:


<u>The Sun's surface temperature is about 5,500 degrees Celsius. </u>


The surface of the Sun is about 5,778 Kelvin. If you want to be exact the sun is 5,505 degrees Celsius and that's just the surface. The corona gets even hotter reaching about 10 million degrees Celsius. The other information about the Sun is correct.

harina [27]3 years ago
4 0

Answer: Option (c) is the correct answer.

Explanation:

Sun is a large star and as it is given that it's diameter is 1,393,000 km. Since there are nuclear reactions that take place inside the Sun, therefore, there is emission of lot of radiations.

As a result, lot of heat energy is there. So, the statement at the surface Sun’s temperature is about 550 degrees Celsius will be an error.

Thus, we can conclude that this error is identified by the statement the Sun’s surface temperature is about 5500 degrees Celsius.

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What units must the constant G have in order for the u it’s F to be newtons (N)?
EleoNora [17]

The units for G must be [N][m^2][kg^{-2}]

Explanation:

The magnitude of the gravitational force between two objects is given by:

F=G\frac{m_1 m_2}{r^2}

where

F is the force

G is the gravitational constant

m_1, m_2 are the masses of the two objects

r is the separation between the objects

We know that:

  • The units of F are Newtons (N)
  • The units of m_1,m_2 are kilograms (kg)
  • The units of r are metres (m)

So, we can rewrite the equation in terms of G, to find its units:

G=\frac{Fr^2}{m_1 m_2}=\frac{[N][m]^2}{[kg][kg]}=[N][m^2][kg^{-2}]

Learn more about gravitational force:

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5 0
2 years ago
The cabinet is mounted on coasters and has a mass of 45 kg. The casters are locked to prevent the tires from rotating. The coeff
stira [4]

Answer:

the force P required for impending motion is 132.3 N

the largest value of "h" allowed if the cabinet is not to tip over is 0.8 m

Explanation:

Given that:

mass of the cabinet  m = 45 kg

coefficient of static friction μ =  0.30

A free flow body diagram illustrating what the question represents is attached in the file below;

The given condition from the question let us realize that ; the casters are locked to prevent the tires from rotating.

Thus; considering the forces along the vertical axis ; we have :

\sum f_y =0

The upward force and the downward force is :

N_A+N_B = mg

where;

\mathbf { N_A  \ and  \ N_B} are the normal contact force at center point A and B respectively .

N_A+N_B = 45*9.8

N_A+N_B = 441    ------- equation (1)

Considering the forces on the horizontal axis:

\sum f_x = 0

F_A +F_B  = P

where ;

\mathbf{ F_A \ and \ F_B } are the static friction at center point A and B respectively.

which can be written also as:

\mu_s N_A + \mu_s N_B  = P

\mu_s( N_A +  N_B)  = P

replacing our value from equation (1)

P = 0.30 ( 441)    

P = 132.3 N

Thus; the force P required for impending motion is 132.3 N

b) Since the horizontal distance between the casters A and B is 480 mm; Then half the distance = 480 mm/2 = 240 mm = 0.24 cm

the largest value of "h" allowed for  the cabinet is not to tip over is calculated by determining the limiting condition  of the unbalanced torque whose effect is canceled by the normal reaction at N_A and it is shifted to N_B:  

Then:

\sum M _B = 0

P*h = mg*0.24

h =\frac{45*9.8*0.24}{132.3}

h = 0.8 m

Thus; the largest value of "h" allowed if the cabinet is not to tip over is 0.8 m

6 0
3 years ago
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