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RoseWind [281]
3 years ago
13

Use the electron-dot notation to demonstrate the formation of an ionic compound involving the elements Al and S

Chemistry
1 answer:
Elden [556K]3 years ago
5 0

Answer:

Al will have 3 dots

S will have 6 dots

Explanation:

Al is in group 13 or roman nummeral 3 so it will have 3 dots. S is in group 16 or roman nummeral 6 so it will have 6 dots.

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Dmitri Mendeleev’s periodic law states that the chemical and physical properties repeat themselves in groups of
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B, it’s in groups of 8
4 0
4 years ago
Elements are organized on the periodic table based on their properties. Which statement correctly predicts and explains the chem
Elanso [62]

Answer is: a. Rubidium (Rb) is more reactive than strontium (Sr) because strontium atoms must lose more electrons.

The ionization energy (Ei) is the minimum amount of energy required to remove the valence electron, when element lose electrons, oxidation number of element grows (oxidation process).  

Alkaline metals (group 1), in this example rubidium, have lowest ionizations energy and easy remove valence electrons (one electron), they are most reactive metals.

Earth alkaline metals (group 2), in this example strontium, have higher ionization energy than alkaline metals, because they have two valence electrons, they are less reactive.  

Rubidium electron configuration: ₃₇Rb 1s²2s²2p⁶3s²3p⁶3d¹⁰4s²4p⁶5s¹; one valence electron is 5s¹ orbital.

Strontium electron configuration: ₃₈Sr 1s²2s²2p⁶3s²3p⁶3d¹⁰4s²4p⁶5s²; two valence electrons is 5s² orbital.

7 0
3 years ago
Read 2 more answers
What would changing the number of electrons in a atom change
aksik [14]

Answer:

The mass of the atom will change

Explanation:

The mass of the atom will alter if the changing the amount of electrons in an atom charge would result in being positively or negatively charged  (Correct me if I'm incorrect sorry If I got this wrong)

3 0
3 years ago
PCL was mixed with gelatin to make a blend for elctrospun fibrous scaffold encapsulating growth factor that was admixed in the p
shusha [124]

Answer:

Explanation:

First PCL to form a scaffold, combined with gelatin.

They are made by first three forms A) made by just PCL.B) made by gelatin ratio PCL is 3:1 and last is C) made by gelatin PCL.

The decoration rate is 1%, 25% and 50% respectively.

<em>A) Growth factor is stuck in 21 days, and can not spread. In this case in vivo experiment for 7 days used highly degradable scaffold use the ability to break down due to decomposition in vivo degradation rate depends on the scaffold's acid byproduct impact.</em>

B) the amount of scaffolded degradation.

First, with scaffold A.

10 mg scaffold weight A= 1 per cent degradation.

Following degradation wt is 9.967=? Degradation per cent.

So, degradation (9.967* 1)/10= 0.9967 per cent.

Likewise for C) scaffold c 10 mg wt. Loss of 50 per cent.

After wt 8.33=? Degradation per cent.

Degradation (8.33* 50)/10=41.65 per cent.

Scaffold c degrades significantly, since the loss of wt is even greater.

7 0
4 years ago
Molarity, is the concentration of a solution expressed in terms of moles solute per liter of solution. What is the molarity of a
pishuonlain [190]

molarity of the CuSO₄ solution = 0.68 moles/L

Explanation:

The formula for molar concentration is:

molar concentration (molarity) = number of moles / solution volume (L)

number of moles = mass / molecular weight

number of moles of CuSO₄ = 12.304 / 159.6

number of moles of CuSO₄ = 0.07709 moles

molar concentration of the CuSO₄ solution = 0.07709 / 0.1127

molar concentration of the CuSO₄ solution = 0.68 moles/L

Learn more about:

molarity

brainly.com/question/13898480

#learnwithBrainly

8 0
4 years ago
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