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777dan777 [17]
3 years ago
14

The effort is always less than the load for a second-class lever. true or false

Physics
2 answers:
ddd [48]3 years ago
8 0
False




Have a nice day
Rasek [7]3 years ago
5 0
False is the answer
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Please let justvibefam answer this ^^
astraxan [27]

Answer:

A. models

they look at it make a model study the model.

7 0
3 years ago
Read 2 more answers
A bungee jumped of mass m jumps off a brodge. Assume that the bungee cord behaves like an ideal spring of srping constant k when
anzhelika [568]

Answer:

The magnitude of the acceleration is at its maximum value.

Acceleration = \frac{-Ak}{m} (m/s)^{2}

Explanation:

During simple harmonic motions such as the oscillation of a spring, at the two extremes of the motion, the acceleration of the mass becomes maximum. This is because this is the point where the force on the body  is maximum.

The angular velocity \omega=\sqrt{\frac{k}{m} }

At points of maximum extension x, the maximum acceleration is given by the formula.

a=-A\omega^{2}

substituting in the value for \omega, this implies that

a= -A\times (\sqrt{\frac{k}{m} } )^{2}

⇒a=\frac{-Ak}{m} (m/s)^{2}

4 0
3 years ago
A 1210-kg vehicle is moving along a horizontal surface with a speed of 28.3 m/s. What work (in J) must be done by the brakes to
ArbitrLikvidat [17]

Answer:

4.85*10^5 Joules

Explanation:

The work done in bringing the car to rest would be equivalent to the kinetic energy of the vehicle while it is in motion.

The kinetic energy of the vehicle is 1/2mv^2; where m is the mass and v is the velocity.

Work done=1/2*1210*28.3^2

Another approach would be to calculate the force applied and the braking distance of the vehicle and then applying the formula of work done. However, it would've been an unnecessary hassle.

6 0
3 years ago
Which of the following is not a requirement of practical fuel
Diano4ka-milaya [45]
Nothing on that  list of choices is a requirement.
4 0
4 years ago
A future use of space stations may be to provide hospitals for severely burned persons. It is very painful for a badly burned pe
inessss [21]

Answer:

1.5min

Explanation:

To solve the problem it is necessary to take into account the concepts related to Period and Centripetal Acceleration.

By definition centripetal acceleration is given by

a_c = \frac{V^2}{r}

Where,

V = Tangencial velocity

r = radius

With our values we know that

a_c = \frac{V^2}{r}

\frac{V^2}{r} = \frac{1}{10}g

Therefore solving to find V, we have:

V = \sqrt{\frac{1}{10}g*r}

V = \sqrt{\frac{9.81*200}{10}}

V = 14m/s

For definition we know that the Time to complete are revolution is given by

t = \frac{Perimeter}{Speed}

t = \frac{2\pi R}{V}

t = \frac{2\pi * 200}{14}

t = 1.5min

6 0
3 years ago
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