The plates of a parallel-plate capacitor are oppositely charged and attract each other. Find the expression for the force one pl
ate exerts on the other.
1 answer:
The force exerted by one plate for two parallel plates arrangement is F = QE/2.
<h3>
Force one plate exerts on the other</h3>
The force exerted by one plate for two parallel plates arrangement is given as follows;
F = QE/2
where;
- Q is the charge on one plates
- E is the electric field due to the charge
- F is force exerted by one plate
Thus, the force exerted by one plate for two parallel plates arrangement is F = QE/2.
Learn more about force between parallel plates here: brainly.com/question/13590045
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