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lesantik [10]
2 years ago
10

The plates of a parallel-plate capacitor are oppositely charged and attract each other. Find the expression for the force one pl

ate exerts on the other.
Physics
1 answer:
Mamont248 [21]2 years ago
5 0

The force exerted by one plate for two parallel plates arrangement is F = QE/2.

<h3>Force one plate exerts on the other</h3>

The force exerted by one plate for two parallel plates arrangement is given as follows;

F = QE/2

where;

  • Q is the charge on one plates
  • E is the electric field due to the charge
  • F is force exerted by one plate

Thus, the force exerted by one plate for two parallel plates arrangement is F = QE/2.

Learn more about force between parallel plates here: brainly.com/question/13590045

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Acceleration = ( final velocity - intial velocity ) / time

= (60-0)m/s / 3s
= 20 m/s2
the answer is a
5 0
3 years ago
The inductance of a closely packed coil of 560 turns is 8.9 mH. Calculate the magnetic flux through the coil when the current is
Y_Kistochka [10]

Answer:

0.11\times 10^{-6}weber

Explanation:

We have given number of turns N = 560

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Current through the coil = 7 mA

Inductance of the coil is given as L=\frac{N\Phi }{I}

Where N  is number of turns I is current and \Phi is flux

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6 0
3 years ago
Read 2 more answers
A circuit contains two devices that are connected in parallel. If the resistance of one of these devices is 12 ohms and the resi
finlep [7]

<u>Answer</u>

3 Ohms

<u>Explanation</u>

when the resistors are in series, the resistance in the circuit increases. For example, if two resistors, R1 and R2 are in series, the combined resistance is R1+R2.

When connected in parallel, the total resistance is the reciprocal of (1/R1 + 1/R2)

In this case the resistors are in parallel.

Total resistance = (1/12 + 1/4)⁻¹

= (1/3)⁻¹

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7 0
3 years ago
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What are the answers please help
aleksandr82 [10.1K]

Answer:

a.) The main scale reading is 10.2cm

b.) Division 7 = 0.07

c.) 10.27 cm

d.)  10.31 cm

e.)  10.24 cm  

Explanation:

The figure depicts a vernier caliper readings

a.) The main scale reading is 10.2 cm

The reading before the vernier scale

b.) Division 7 = 0.07

the point where the main scale and vernier scale meet

c.) The observed readings is

10.2 + 0.07 = 10.27 cm

d.) If the instrument has a positive zero error of 4 division

correct reading = 10.27 + 0.04 = 10.31cm

e.)  If the instrument has a negative zero error of 3 division

correct reading = 10.27 - 0.03 = 10.24cm  

3 0
3 years ago
What kind of friction is occurring between a pencil and desktop when you flick the pencil?
DanielleElmas [232]
The third one sliding friction
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2 years ago
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