The current flowing in each resistor of the circuit is 4 A.
<h3>
Equivalent resistance of the series resistors</h3>
The equivalent resistance of the series circuit is calculated as follows;
6 Ω and 4 Ω are in series = 10 Ω
5 Ω and 10Ω are in series = 15 Ω
<h3>Effective resistance of the circuit</h3>

<h3>Current flowing in the circuit</h3>
V = IR
I = V/R
I = 24/6
I = 4 A
Learn more about resistors in parallel here: brainly.com/question/15121871
B) Energy from the sun is the answer, I am sure;
The water cycle is driven primarily by the energy from the sun<span>
. This </span>
solar energy<span>
drives the cycle by evaporating water from the oceans, lakes, rivers, and even the soil. Other water moves from plants to the atmosphere through the process of transpiration.</span>
Answer:
0.25 m
Explanation:
We can solve the problem by using the lens equation:

where
f is the focal length
p is the distance of the object from the lens
q is the distance of the image from the lens
In this problem, we have
f = +20 cm=+0.20 m (the focal length is positive for a converging lens)
q = +1.0 m (the image distance is positive for a real image)
Solving the equation for p, we find

Answer:
Explanation: Mechanical advantage is a measure of the force amplification achieved by using a tool, mechanical device or machine system. The device preserves the input power and simply trades off forces against movement to obtain a desired amplification in the output force.
IM sure there is C, D, and E in kuiper belts, but not really sure of silicon and iron