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lesantik [10]
2 years ago
10

The plates of a parallel-plate capacitor are oppositely charged and attract each other. Find the expression for the force one pl

ate exerts on the other.
Physics
1 answer:
Mamont248 [21]2 years ago
5 0

The force exerted by one plate for two parallel plates arrangement is F = QE/2.

<h3>Force one plate exerts on the other</h3>

The force exerted by one plate for two parallel plates arrangement is given as follows;

F = QE/2

where;

  • Q is the charge on one plates
  • E is the electric field due to the charge
  • F is force exerted by one plate

Thus, the force exerted by one plate for two parallel plates arrangement is F = QE/2.

Learn more about force between parallel plates here: brainly.com/question/13590045

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A 50-ω resistor is connected to a 9.0 V battery. How much thermal energy is produced in 7.5 minutes?1.2 * 10^2 J1.3 * 10^3 J3.0
emmasim [6.3K]

In order to calculate the thermal energy, first let's calculate the power, using the formula:

P=\frac{V^2}{R}

For a voltage V = 9 Volts and a resistance R = 50 ohms, we have:

\begin{gathered} P=\frac{9^2}{50} \\ P=\frac{81}{50}=1.62\text{ W} \end{gathered}

Now, multiplying the power by the time (in seconds), we can find the energy:

\begin{gathered} E=P\cdot t \\ E=1.62\cdot7.5\cdot60 \\ E=729\text{ J} \end{gathered}

In scientific notation, we have an energy of 7.3 * 10^2 J, therefore the correct option is the fourth one.

4 0
1 year ago
A mass m attached to a spring of constant k is oscillating on a frictionless surface. A second mass of mass m is dropped on top
elixir [45]

Answer:

E. The period of oscillation increases.

Explanation:

The period of oscillation is:

T = 2π√(m/k)

Frequency is the inverse of period (f = 1/T), so as period increases, frequency decreases.

Increasing the mass will increase the period and decrease the frequency.

8 0
3 years ago
The radii of the sprocket assemblies and the wheel of the bicycle in the figure are:
Furkat [3]
To solve this task we have to make a proportion, but firstly we have to set up all the main points : so, the distance is  s=r(B), that has its <span>r=radius,B=angle in rad velocity v=ds/dt= w(r)
Do not forget about </span> w = angular speed in rad/s and w1 = 1 revolution/sec = 2Pi (rad/s)
Now we can go to proportion
v1=v2
w1*r1 = w2r2w2 = w1 * r1/r2 = 2w1 = 4Pi (rad/s)
w2 = w3 (which is the   angular velocity of the rear wheel) &#10;
SOLVING FOR A : v3 = w3 * r3 = 4pi * 14 (inch/s) = 14.66 ft/sec
v3 = 14.66 ft/sec(1 mile/5280 ft)( 3600 sec/h)= 9.99 or something about <span>10 mph --- SOLVING FOR B.
</span>I'm sure it helps!
7 0
3 years ago
A nonzero net force acts on a particle and does work. Which one of the following statements is true?
arlik [135]

Answer:

option (D) is correct.

Explanation:

According to the work energy theorem, the work done by all forces is equal to the change in kinetic energy of the body.

the kinetic energy of a body is directly proportional to the square of the speed of the body.

As the kinetic energy change, the speed of the body also change.

Option (D) is correct.

5 0
3 years ago
One side of the moon always faces Earth because the time it takes the moon to spin on its axis is blank the time it takes the mo
Kamila [148]
The word to fill in the blank is "equal". Because the time taken to rotate (spin on its axis) is equal to the time of revolution (going around the earth), this means that both have the same rate of angular rotation. So for every bit that the moon goes around its orbit around earth, the moon itself rotates accordingly to present the exact same side to earth.
6 0
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