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lesantik [10]
2 years ago
10

The plates of a parallel-plate capacitor are oppositely charged and attract each other. Find the expression for the force one pl

ate exerts on the other.
Physics
1 answer:
Mamont248 [21]2 years ago
5 0

The force exerted by one plate for two parallel plates arrangement is F = QE/2.

<h3>Force one plate exerts on the other</h3>

The force exerted by one plate for two parallel plates arrangement is given as follows;

F = QE/2

where;

  • Q is the charge on one plates
  • E is the electric field due to the charge
  • F is force exerted by one plate

Thus, the force exerted by one plate for two parallel plates arrangement is F = QE/2.

Learn more about force between parallel plates here: brainly.com/question/13590045

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