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3 years ago

8

Waves that can travel only through a medium are called waves. Sound waves are waves. (Hint: same w

ord fills in both blanks)

1 answer:

Nana76 [90]3 years ago

6 0

First blank is radiator

Second blank is radiator

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A ball thrown straight up climbs for 3.0 sec before falling. Neglecting air resistance, with what velocity was the ball thrown?

sesenic [268]

Answer:

Speed, u = 29.4 m/s

Explanation:

Given that, A ball thrown straight up climbs for 3.0 sec before falling, t = 3 s

Let u is speed with which the ball is thrown up. When the ball falls, v = 0

Using first equation of motion as :

v = u + at

Here, a = -g

So, u = g × t

$u=9.8\times 3$

u = 29.4 m/s

So, the speed with which the ball was thrown is 29.4 m/s. Hence, this is the required solution.

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4 years ago

. Alpha-emitting substances, such as radon gas, can be a serious health hazard only if _____. their radiation strikes the skin t

Masja [62]

Answer:Answer:

They are inhaled or eaten

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3 years ago

What was the trail of tears?

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3 years ago

Based on what you have just read, what are the advantages of storing music digitally compared to using an analog system?

melamori03 [73]

Storing music digitally requires less storage room than analog records or tapes. Digital music is easier to copy and the copies are the same as the original. The quality of the signal does not degrade over long periods of time.

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3 years ago

Read 2 more answers

An object of mass 1.0 kg is at rest on a smooth inclined plane with height h, length 8 m,

TEA [102]

The coefficient of kinetic friction for the rough horizontal surface is 0.66.

The given parameters;

<em>mass of the object, m = 1 kg</em>
<em>length of the inclined plane, L = 8 m</em>
<em>angle of inclination of the plane, θ = 30⁰ </em>
<em>distance traveled before hitting the spring, d₁ = 4 m</em>
<em>distance traveled after hitting the spring, d₂ = 1.3 m</em>
<em>the spring constant, k = 26.5 N/m</em>

Apply work-energy theorem; the work done the force of friction is equal to the energy stored in the spring.

$F_kd_1 = \frac{1}{2} kd_2^2\\\\\mu_kmg cos(\theta)d_1 = \frac{1}{2} kd_2^2\\\\\mu_k(1 \times 9.8 \times cos(30)\times 4) = \frac{1}{2} \times 26.5 \times (1.3)^2\\\\33.95\mu_k = 22.39\\\\\mu_k = \frac{22.39}{33.95} \\\\\mu_k = 0.66$

Thus, the coefficient of kinetic friction for the rough horizontal surface is 0.66.

Learn more here:brainly.com/question/10063455

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3 years ago