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Naddika [18.5K]
3 years ago
10

Identify the energy transformations in the following actions.

Physics
2 answers:
bazaltina [42]3 years ago
8 0

Answer:

a)Mechanical to heat energy.

b)potential to kinetic energy

c)kinetic to potential energy

d)kinetic to heat energy.

Artemon [7]3 years ago
4 0
According to the Law of Conservation of Energy, energy is neither created nor destroyed. It is only transferred through different forms of energy. For the following situations, the conversion of energy is as follows:

*Turning on a space heater = electrical energy⇒heat energy
*Dropping an apple core into the garbage =  potential energy⇒kinetic energy
*Climbing up a rope ladder = kinetic energy⇒potential energy
*Starting a car = chemical energy⇒mechanical energy
<span>*Turning on a flashlight = chemical energy</span>⇒electrical energy
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The top of the pool table is 0.810 m from the floor. the placement of the tape is such that 0 m is aligned with the edge of the
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Compute first for the vertical motion, the formula is:

y = gt²/2 

0.810 m = (9.81 m/s²)(t)²/2 

t = 0.4064 s 


whereas the horizontal motion is computed by: 

x = (vx)t 

4.65 m = (vx)(0.4064 s) 

4.65 m/ 0.4064s = (vx)

(vx) = 11.44 m / s
So look for the final vertical speed. 

(vy) = gt 

(vy) = (9.81 m/s²)(0.4064 s) 

(vy) = 3.99 m/s 


speed with which it hit the ground: 

v = sqrt[(vx)² + (vy)²] 

v = sqrt[(11.44 m/s)² + (3.99 m/s)²] 

v = 12.12 m / s
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3 years ago
It is correct to say that impulse is equal toA) momentum.B) the change in momentum.C) the force multiplied by the distance the f
Elena-2011 [213]

Answer:

B) the change in momentum.

Explanation:

The impulse is defined as the product between the force applied on an object (F) and the duration of the collision (\Delta t):

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J=ma \Delta t

Now we can also rewrite the acceleration as ratio between the change in velocity and change in time: a=\frac{\Delta v}{\Delta t}. If we substitute into the previous equation, we find

J=m\frac{\Delta v}{\Delta t}\Delta t=m\Delta v

And the quantity m\Delta v is equivalent to the change in momentum, \Delta p.

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c

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