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satela [25.4K]
3 years ago
5

A 4.0 kg box is released from rest on a frictionless ramp. The box slides from the ramp onto a rough horizontal

Physics
2 answers:
muminat3 years ago
4 0

Answer:

Assuming air resistance is negligible, all of the potential energy that the object has at the top of the ramp is converted into kinetic energy by the time it gets to the bottom of the ramp.  This is because no matter what path the object takes to move the 5m vertically (ie. falling straight down v. sliding on the ramp), gravity does the same amount of work on it.

Thus, calculate the total amount of potential energy at the top of the ramp:

Ep=mgh

Ep=4(9.81)5

Ep=196.2 Joules

Because all of this potential energy is converted into kinetic energy in the object by the bottom of the ramp, the object hits the spring with 196.2J of energy.

By using the formula for elastic potential energy, you can calculate exactly how far the spring compresses.

196.2=(1/2)k(x^2)

392.4=(350)(x^2)

1.1211=x^2

sqrt(1.1211)=x

x=1.059m

As for the last part of the question, after the object compresses the spring fully and stops momentarily, the spring converts it's elastic potential energy back into kinetic energy in the object and pushes it away again.

Explanation:

kirza4 [7]3 years ago
4 0

Answer:

1.0m

Explanation:

khan

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1. A 3.0 kg mass is tied to a rope and swung in a horizontal circle. If the velocity of the mass is 4.0 ms and
saul85 [17]

10.67m/s²

32N

Explanation:

Given parameters:

Mass of the body = 3kg

velocity of the mass = 4m/s

radius of circle = 0.75m

Unknown:

centripetal acceleration = ?

centripetal force = ?

Solution:

The centripetal force is the force that keeps a radial body in its circular motion. It is directed inward:

   Centripetal acceleration  = \frac{v^{2} }{r}

   v is the velocity of the body

    r is the radius of the circle

  putting in the parameters:

   Centripetal acceleration = \frac{4^{2} }{0.75}

    Centripetal acceleration = 10.67m/s²

Centripetal force = m  \frac{v^{2} }{r}

          m is the mass

 Centripetal force = mass x centripetal acceleration

                              = 3 x 10.67

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learn more:

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3 years ago
Question 25 of 30
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Answer:

it's B. circuit a and b are series circuit while c is parallel

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A 2.00-m rod of negligible mass connects two very small objects at its ends. The mass of one object is 1.00 kg and the mass of t
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Answer:

<h2> 4kg</h2>

Explanation:

Step one:

given

length of rod=2m

mass of object 1 m1=1kg

let the unknown mass be x

center of mass<em> c.m</em>= 1.6m

hence 1kg is 1.6m from the <em>c.m</em>

and x is 0.4m from the <em>c.m</em>

Taking moment about the <em>c.m</em>

<em>clockwise moment equals anticlockwise moments</em>

1*1.6=x*0.4

1.6=0.4x

divide both sides by 0.4 we have

x=1.6/0.4

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3 years ago
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