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svet-max [94.6K]
3 years ago
12

What are three of Leonardo divinci's contributions to science?

Chemistry
1 answer:
Zielflug [23.3K]3 years ago
5 0
<span> hydraulic pumps, flying machines, and war machines.</span>
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What is the pH of a substance with a hydrogen concentration of 1.0 x 10-13?
Nikolay [14]

Answer:

Favorite Answer

1.0 x10^-14 = (1.0 x 10^-13) (x)

x = 1.0 x 10^-1 = 0.1 M (this is the [OH-])

pOH = -log 0.1 = 1.0

Explanation:

I hope this helps :) sorry if not :(

4 0
3 years ago
use the internet to look up the sds for 2.0 m sodium hydroxide naoh to answer the following question a) list the potential acute
VashaNatasha [74]

A safety data sheet is informational data that states the properties of the various chemicals. According to the SDS of NaOH, it causes irritation, nausea, eye burn, burns in the digestive system, etc.

<h3>What is SDS?</h3>

SDS is abbreviated for a safety data sheet which is a document that provides information on the chemicals including the properties, health hazards, measures, safety, prevention, etc.

According to SDS, NaOH results in various potential acute health effects including vomiting, diarrhea, nausea, irritation, etc. The chronic effect includes coma, burns in the eye, respiratory infection, digestive system, dermatitis, etc.

Therefore, sodium hydroxide has various acute and chronic health effects.

Learn more about SDS, here:

brainly.com/question/2471127

#SPJ4

Your question is incomplete, but most probably your full question was, Use the internet to look up the sds for 2.0 m sodium hydroxide, NaOH, to answer the following question: list the potential acute and chronic health effects.

6 0
1 year ago
1. Be able to convert atm’s to kPa’s. (how?)
Whitepunk [10]
1.) 0.875atm x 760.0 mmHg/atm
2.)    8I
        7I                                        0
        6I                                      0
        5I                                    0
        4I                                  0
        3I                                0
        2I--------- 000000000 0I
        1I-0------------------------ I---------------        
         0             50             100           150
                      Boiling point(degrees Celsius)
3.) The warmer the molecules are the faster they move like boiling water the gases are coming out of the water
4.)no clue
5.) A {solution} is always transparent, light passes through with no scattering from solute particles which are the molecule in size. The solution is homogeneous and does not settle out. A solution cannot be filtered but can be separated using the process of distillation.

A {suspension} is cloudy and heterogeneous. The particles are larger than 10,000 Angstroms which allows them to be filtered. If a suspension is allowed to stand the particles will separate out.

<span>A {colloid} is intermediate between a solution and a suspension. While a suspension will separate out a colloid will not. Colloids can be distinguished from solutions using the Tyndall effect. Light passing through a colloidal dispersion, such as smoky or foggy air, will be reflected by the larger particles and the light beam will be visible. A hydrocolloid can simply be defined as a substance that forms a gel when it comes in contact with water. Such substances include both polysaccharides and proteins.
6.)</span><span>The random movement of microscopic particles suspended in a liquid or gas, caused by collisions with molecules of the surrounding medium. Also called Brownian motion, molecular movement, pedesis.
hope that helps please mark me as brainly 
</span>
5 0
3 years ago
Calculate the unit cell edge length for an 78 wt% Ag- 22 wt% Pd alloy. All of the palladium is in solid solution, and the crysta
BaLLatris [955]

Answer:

The unit cell edge length for the alloy is 0.405 nm

Explanation:

Given;

concentration of Ag, C_{Ag} = 78 wt%

concentration of Pd, C_P_d = 22 wt%

density of Ag = 10.49 g/cm³

density of Pd = 12.02 g/cm³

atomic weight of Ag, A_A_g = 107.87 g/mol

atomic weight of iron, A_P_d = 106.4 g/mol

Step 1: determine the average density of the alloy

\rho _{Avg.} = \frac{100}{\frac{C_A_g}{\rho _A_g} + \frac{C__{Pd}}{\rho _{Pd}} }

\rho _{Avg.} = \frac{100}{\frac{78}{10.49} + \frac{22}{12.02} } = 10.79 \ g/cm^3

Step 2: determine the average atomic weight of the alloy

A _{Avg.} = \frac{100}{\frac{C_v}{A _A_g} + \frac{C__{Pd}}{A _{Pd}} }

A _{Avg.} = \frac{100}{\frac{78}{107.87} + \frac{22}{106.4} } = 107.54 \ g/mole

Step 3: determine unit cell volume

V_c=\frac{nA_{avg.}}{\rho _{avg.} N_a}

for a FCC crystal structure, there are 4 atoms per unit cell; n = 4

V_c=\frac{4*107.54}{ 10.79*6.022*10^{23}} = 6.620*10^{-23} \ cm^3/cell

Step 4: determine the unit cell edge length

Vc = a³

a = V_c{^\frac{1}{3} }\\\\a = (6.620*10^{-23}}){^\frac{1}{3}}\\\\a = 4.05 *10^{-8} \ cm= 0.405 nm

Therefore, the unit cell edge length for the alloy is 0.405 nm

7 0
3 years ago
you have an object with mass of 86 g and volume of 10 cm^3 (cubed). calculate density, show your work, and identify which materi
sleet_krkn [62]

Answer:

8.6g/cm³ (BRASS)

Explanation:

Given the following :

Mass of object = 86g

Volume of object = 10cm³

The density of an object is calculated using the formula :

Density(g/cm³) = mass(g) / volume(cm³)

Inputting our values :

Density = 86g / 10cm³

Density = 8.6g/cm³

According to the table provided, the object which corresponds to having a density of 8.6g/cm³ is BRASS

6 0
3 years ago
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