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3 years ago

Balancing Equations: _(NH4)3PO4 + _Pb(NO3)4 = _Pb3(PO4)4 + _NH4NO3 With work please.

Chemistry

1 answer:

Svetlanka [38]3 years ago

8 0

1)4
2)3
3)0
4)12
4(NH4)3 + 3Pb(NO3)4= Pb3(PO4)4 +12NH4NO3

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Are they all correct?

Degger [83]

Answer:yes

Explanation:

7 0

3 years ago

Read 2 more answers

The product side of a chemical reaction is shown.

Inga [223]

The number that represents the coefficient on the product side of the chemical reaction, $-- > 7Ti_2(SO_4)_3$ is 7.

<h3>Coefficients of chemical equations</h3>

In equations representing chemical reactions, the coefficient of each reactant or product of a reaction is the number that comes on the left-hand side just before the chemical formula.

The coefficient of each species in a chemical reaction is obtainable when the equation of the reaction is balanced.

For example, in the following equation: 2A + B = 3C + D

The coefficients of A, B, C, and D are 2, 1, 3, and 1 respectively.

Applying this to the product side of a chemical reaction; $-- > 7Ti_2(SO_4)_3$

It means that the coefficient of the product is 7.

More on coefficients of chemical equations can be found here: brainly.com/question/28294176

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1 year ago

The target diol is synthesized in one step from 1-methylcyclopentene, but your lab partner exhausted the supply of that alkene.

andrezito [222]

Answer:

The reagents are $CH_{3}CH_{3}O^{-},OsO_{4},NaHSO_{3}and H_{2}O$ .

Explanation:

1-Methylenecyclopentene is treated with HBr form 1-bromo-1-methylcyclopentane, which is treated with strong base ethoxide ion and forms 1-methylcyclopent-1-ene.

This alkene is treated with osmium tetraoxide in the presence of sodium bisulfite to form target product.

The chemical reaction is as follows.

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3 years ago

Is cold water more dense

Paraphin [41]

Cold water<span> is </span>more dense<span> and will sink in room-temperature </span>water<span>. hope it helps :)</span>

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3 years ago

What is the ionic compound of Na^+ and CO3^2-

maksim [4K]

To find the chemical formula of an ionic compound, the first step is to find the charge of the 2 ions. As given already, the charge of sodium ion is 1+, and carbonate ion has a charge of 2-. We can picture it like that: Sodium ion loses 1 electron and carbonate ion gains 2.

The next step is to find how the 2 ions can lose and gain electrons equally. In this case, since each Na ion only loses 1 electron, it cannot satisfy the need of one carbonate ion, since they need 2, not 1. Therefore, 2 Na ions can cover the need of one carbonate ion. So, the ratio of Na to CO3 ion should be 2:1.

Now just combine the 2 ions, positive one at the front, which makes it NaCO3, make sure you do not add the charge and notice that CO3 is a molecule itself so do not remove the 3. Now because the ratio is 2:1, so the final formula is Na2CO3, no need to add 1 if the ratio is 1.

Your answer should be Na2CO3.

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3 years ago