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Otrada [13]
3 years ago
8

Which electromagnetic waves are used in ovens and cell phone communications

Chemistry
2 answers:
yuradex [85]3 years ago
8 0
Thermal energy
hope it helps!
densk [106]3 years ago
7 0
Ovens use microwaves. Believe it or not, thats the name
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How do the interactions that are broken in water when it is boiled compare with those broken when water is electrolyzed? Boiling
nasty-shy [4]

Answer:

Boiling water breaks intermolecular attractions and electrolysis breaks covalent bonds.

Explanation:

When water boils, hydrogen bonds are broken between adjacent water molecules. The hydrogen bond is an intermolecular bond between adjacent oxygen and hydrogen atoms of water molecules.  

During electrolysis, water dissociates in the presence of electric current. Here, ions are formed in the process. Therefore, covalent bonds are broken here.

8 0
3 years ago
Why was mass lost from the crucible during the reaction?
Alexxandr [17]
If the crucible wasn't covered with a lid the reactants may have produced a gas that was released into the surroundings, or mass may have been lost in the form of water vapour.
6 0
3 years ago
A method used by the U.S. Environmental Protection Agency (EPA) for determining the concentration of ozone in air is to pass the
baherus [9]

Answer: 1. 9.08\times 10^{-6} moles

2. 90 mg

Explanation:

O_3(g)+2NaI(aq)+H_2O(l) \rightarrow O_2(g)+I_2(s)+2NaOH(aq)

According to stoichiometry:

1 mole of ozone is removed by 2 moles of sodium iodide.

Thus 4.54 \times 10^{-6} moles of ozone is removed by =\frac{2}{1}\times 4.54 \times 10^{-6}=9.08\times 10^{-6} moles of sodium iodide.

Thus 9.08\times 10^{-6} moles of sodium iodide are needed to remove 4.54\times 10^{-6} moles of O_3

2. \text{Number of moles of ozone}=\frac{0.01331g}{48g/mol}=0.0003moles

According to stoichiometry:

1 mole of ozone is removed by 2 moles of sodium iodide.

Thus 0.0003 moles of ozone is removed by =\frac{2}{1}\times 0.0003=0.0006 moles of sodium iodide.

Mass of sodium iodide= moles\times {\text {molar mass}}=0.0006\times 150g/mol=0.09g=90mg    (1g=1000mg)

Thus 90 mg of sodium iodide are needed to remove 13.31 mg of O_3.

3 0
3 years ago
Which is stronger ph4 or ph6
Temka [501]

Answer:

ph4 is stronger

Explanation:

4 is the only moderate

5 - 6 are weak acids

0 - 3 are strong

7 0
3 years ago
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A representative particle of carbon dioxide is
KonstantinChe [14]
Carbon atom with iron and helium
6 0
3 years ago
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