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nordsb [41]
3 years ago
8

Why are the boiling point and freezing point of solutions affected by the concentration of solute particles?

Chemistry
1 answer:
Salsk061 [2.6K]3 years ago
8 0
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Problem PageQuestion A chemist makes of magnesium fluoride working solution by adding distilled water to of a stock solution of
igomit [66]

Answer:

5.37 × 10⁻⁴ mol/L

Explanation:

<em>A chemist makes 660. mL of magnesium fluoride working solution by adding distilled water to 230. mL of a 0.00154 mol/L stock solution of magnesium fluoride in water. Calculate the concentration of the chemist's working solution. Round your answer to 3 significant digits.</em>

Step 1: Given data

  • Initial concentration (C₁): 0.00154 mol/L
  • Initial volume (V₁): 230. mL
  • Final concentration (C₂): ?
  • Final volume (V₂): 660. mL

Step 2: Calculate the concentration of the final solution

We want to prepare a dilute solution from a concentrated one. We can calculate the concentration of the final solution using the dilution rule.

C₁ × V₁ = C₂ × V₂

C₂ = C₁ × V₁ / V₂

C₂ = 0.00154 mol/L × 230. mL / 660. mL = 5.37 × 10⁻⁴ mol/L

5 0
2 years ago
Historically the troubadour was a ____.
eimsori [14]

Composer and performer of Old Occitan lyric poetryduring the High Middle Ages (1100–1350). Since the word troubadour is etymologically masculine, a female troubadour is usually called a trobairitz.


6 0
3 years ago
PLZ HELP ME WITH MY WORK​
Delvig [45]

Answer:

neutrons should be added with the protons

4 0
2 years ago
At 35.0°c and 3.00 atm pressure, a gas has a volume of 1.40 l. what pressure does the gas have at 0.00°c and a volume of 0.950 l
Leona [35]

Answer : The pressure of gas will be, 3.918 atm and the combined gas law is used for this problem.

Solution :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 3 atm

P_2 = final pressure of gas = ?

V_1 = initial volume of gas = 1.40 L

V_2 = final volume of gas = 0.950 L

T_1 = initial temperature of gas = 35^oC=273+35=308K

T_2 = final temperature of gas = 0^oC=273+0=273K

Now put all the given values in the above equation, we get the final pressure of gas.

\frac{3atm\times 1.40L}{308K}=\frac{P_2\times 0.950L}{273K}

P_2=3.918atm

Therefore, the pressure of gas will be, 3.918 atm and the combined gas law is used for this problem.

4 0
3 years ago
Read 2 more answers
The molecular weight of a gas that has a density of 5.75 g/l at stp is __________ g/mol.
Ira Lisetskai [31]

Answer : The molecular weight of a gas is, 128.9 g/mole

Explanation : Given,

Density of a gas = 5.75 g/L

First we have to calculate the moles of gas.

At STP,

As, 22.4 liter volume of gas present in 1 mole of gas

So, 1 liter volume of gas present in \frac{1}{22.4}=0.0446 mole of gas

Now we have to calculate the molecular weight of a gas.

Formula used :

\text{Moles of gas}=\frac{\text{Mass of a gas}}{\text{Molecular weight of a gas}}

Now put all the given values in this formula, we get the molecular weight of a gas.

0.0446mole=\frac{5.75g}{\text{Molecular weight of a gas}}

\text{Molecular weight of a gas}=128.9g/mole

Therefore, the molecular weight of a gas is, 128.9 g/mole

8 0
3 years ago
Read 2 more answers
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