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4 years ago

63b/(-7) what is this solved

Mathematics

1 answer:

NNADVOKAT [17]4 years ago

3 0

Answer:

n=9

Step-by-step explanation:

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Answer:

8x+5w+4

Step-by-step explanation:

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3 years ago

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9!-5!(6!) It is factorials.

Neporo4naja [7]

Answer:

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3 years ago

Find the complete factored form of the

Angelina_Jolie [31]

Answer:

(0 - (9 • (a^666))) - (22•3ab^6)

(0 - 32a^666) - (22•3ab^6)

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-3a • (4b^6 + 3a^665)

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3 years ago

Solve for x given the lines are parallel. (7x - 8) 62°

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Answer:

The answer is 0 ✌

Step-by-step explanation:

70 - 8 =62°

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3 years ago

Jarrett's puppy weighed 3 3/4 ounces at Birth. At 1 week old, the puppy weighed 5 1/8 ounces. At 2 weeks old, the puppy weighed

Ad libitum [116K]

Answer: The answer is $7\dfrac{7}{8}$ ounces.

Step-by-step explanation: Given in the question the weight of Jarrett's puppy at birth, one week old and 2 weeks old are as follows:

$b_0=3\dfrac{3}{4}=\dfrac{15}{4}~\textup{ounces},\\\\\\b_1=5\dfrac{1}{8}=\dfrac{41}{8}~\textup{ounces},\\\\\\b_3=6\dfrac{1}{2}=\dfrac{13}{2}~\textup{ounces}.$

We can see that

$b_1-b_0=b_2-b_1=\dfrac{11}{8}.$

So, the weight of the baby will make an arithmetic progression with first term 'a' and common difference 'd' as follows:

$b_0=\dfrac{15}{4},~~d=\dfrac{11}{8}.$

Thus, the weight of the puupy after 3 weeks will be

$b_3=b_0+3\times d=\dfrac{15}{4}+3\times\dfrac{11}{8}=\dfrac{30+33}{8}=\dfrac{63}{8}=7\dfrac{7}{8}~\textup{ounces}.$

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4 years ago

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