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bulgar [2K]
4 years ago
14

Susan made a deposit of $74 to her bank account she then had $192 in the account how much money was in the account before the de

posit
Mathematics
2 answers:
andre [41]4 years ago
8 0
The meaning of deposit means she added $72 into her bank account after adding $72 into her account she has $192 in her account so if you one to find the original amount of money in her account just take $192 - $74
The answer is : $118
Aleksandr-060686 [28]4 years ago
3 0
Rewind the "mind movie" of what happened. She added $74 to her account and then had $192. Back it up by subtracting the $74 from $192.

192 - 74 = 118
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The nth term of a sequence is 3n + 2
gavmur [86]

Answer:

see explanation

Step-by-step explanation:

To calculate the first 3 terms substitute n = 1, 2, 3 into the n th term rule

a_{1} = (3 × 1) + 2 = 3 + 2 = 5

a_{2} = (3 × 2) + 2 = 6 + 2 = 8

a_{3} = (3 × 3) + 2 = 9 + 2 = 11

------------------------------------------------------------------

substitute n = 10 into the n th term rule

a_{10} = (3 × 10) + 2 = 30 + 2 = 32

3 0
4 years ago
Read 2 more answers
Determine whether the improper integral converges or diverges, and find the value of each that converges.
Temka [501]

Answer:

It diverges.

Step-by-step explanation:

We are given the inetegral:  \int\limits^{\infty}_2 \frac{1}{x} (\ln x)^2 dx

\int\limits^{\infty}_2 \frac{1}{x} (\ln x)^2 dx=\int\limits^{\infty}_2 (\ln x)^2 d(\ln x)=\\\\=\lim_{t \to \infty} \int\limits^t_2 (\ln x)^2d(\ln x)=\lim_{t \to \infty} \frac{(\ln t)^3}{3} |^t_2=\infty-\frac{(\ln 2)^3}{3} =\infty

So it is divergent.

7 0
4 years ago
The coordinates of point A on a grid are (−1, 6). Point A is reflected across the y-axis to obtain point B. The coordinates of p
elena55 [62]
When you reflect across the y axis the y coordinate stays the same and the x coorrdinate changes sign  so x = -1 goes to x = 1

Answer point B is (1,6)
6 0
3 years ago
The following graphs have a scale assigned to them: The area of each grid
dezoksy [38]

The graphs that are density curves for a continuous random variable are: Graph A, C, D and E.

<h3>How to determine the density curves?</h3>

In Geometry, the area of the density curves for a continuous random variable must always be equal to one (1). Thus, we would test this rule in each of the curves:

Area A = (1 × 5 + 1 × 3 + 1 × 2) × 0.1

Area A = 10 × 0.1

Area A = 1 sq. units (True).

For curve B, we have:

Area B = (3 × 3) × 0.1

Area B = 9 × 0.1

Area B = 0.9 sq. units (False).

For curve C, we have:

Area C = (3 × 4 - 2 × 1) × 0.1

Area C = 10 × 0.1

Area C = 1 sq. units (False).

For curve D, we have:

Area D = (1 × 4 + 1 × 3 + 1 × 2 + 1 × 1) × 0.1

Area D = 10 × 0.1

Area D = 1 sq. units (True).

For curve E, we have:

Area E = (1/2 × 4 × 5) × 0.1

Area E = 10 × 0.1

Area E = 1 sq. units (True).

Read more on density curves here: brainly.com/question/26559908

#SPJ1

6 0
2 years ago
Select the correct answer Which equation represents a line that is perpendicular to line MN?
taurus [48]

Answer:

D. y = 4x - 6

Step-by-step explanation:

The equation that is perpendicular to the line MN should have a slope that when multiplied by the slope of line MN will result to negative one. Therefore,

Therefore,

m₁ × m₂ = -1

Using the 2 coordinates of MN let's find the slope,

(-7, 6)(5, 3)

Therefore,

m₁ = 3 - 6 / 5 - (-7) = -3 / 12 = - 1 / 4

The equation that represent a line perpendicular to the line MN is

y = 4x - 6 because the slope slope(m₂) is 4.

From our formula,

4 × - 1 / 4 = - 1

So, option D meets the requirement.

6 0
3 years ago
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