Answer:
4 times
Step-by-step explanation:
Sample space :
6 sided cube = (1, 2, 3, 4, 5, 6)
Coin = (H, T)
Probability = required outcome / Total possible outcomes
Probability of head (H) = P(H) = 1 /2 = 0.5
Probability of 3 = P(3) = 1 /6 = 0.166666
Probability of heads and 3 on a single try = p(H) * p(3) = 0.5 * 0.166666 = 0.083333
Hence, expected number of times this is likely to occur in 48 tries :
0.083333 * 48 = 4
Answer:
ρ_air = 0.15544 kg/m^3
Step-by-step explanation:
Solution:-
- The deflated ball ( no air ) initially weighs:
m1 = 0.615 kg
- The air is pumped into the ball and weight again. The new reading of the ball's weight is:
m2 = 0.624 kg
- The amount of air ( mass of air ) pumped into the ball can be determined from simple arithmetic between inflated and deflated weights of the ball.
m_air = Δm = m2 - m1
m_air = 0.624 - 0.615
m_air = 0.009 kg
- We are to assume that the inflated ball takes a shape of a perfect sphere with radius r = 0.24 m. The volume of the inflated ( air filled ) ball can be determined using the volume of sphere formula:
V_air = 4*π*r^3 / 3
V_air = 4*π*0.24^3 / 3
V_air = 0.05790 m^3
- The density of air ( ρ_air ) is the ratio of mass of air and the volume occupied by air. Expressed as follows:
ρ_air = m_air / V_air
ρ_air = 0.009 / 0.05790
Answer: ρ_air = 0.15544 kg/m^3
The way to work out how much each person gets is to find out how much one part is worth.
We can do this by adding the ratio (1:2) which gives us 3.
Divide £120 by 3 parts and you get £40 as one part.
Because the ratio is one part : two parts, Matt gets £40 and Cat gets £80.
1400kg.
Force=ma
2100N= m*1.5
2100/1.5= 1400kg.
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