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4 years ago

What is earth made of

1 answer:

8 0

Above the core is Earth's mantle, which is made up of rock containing silicon, iron,magnesium, aluminum, oxygen and other minerals. The rocky surface layer of Earth, called the crust, is made up of mostly oxygen, silicon, aluminum, iron, calcium, sodium, potassium and magnesium.

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What is the speed vfinal of the electron when it is 10.0 cm from charge 1?

fgiga [73]

Answer:

Two stationary positive point charges, charge 1 of magnitude 3.45 nC and charge 2 of magnitude 1.85 nC, are separated by a distance of 50.0 cm. An electron is released from rest at the point midway between the two charges, and it moves along the line connecting the two charges. What is the speed v(final) of the electron when it is 10.0 cm from

The answer to the question is

The speed $v_{final}$ of the electron when it is 10.0 cm from charge Q₁

= 7.53×10⁶ m/s

Explanation:

To solve the question we have

Q₁ = 3.45 nC = 3.45 × 10⁻⁹C

Q₂ = 1.85 nC = 1.85 × 10⁻⁹ C

2·d = 50.0 cm

a = 10.0 cm

q = -1.6×10⁻¹⁹C

Also initial kinetic energy = 0 and

Initial electric potential energy = $k\frac{qQ_1}{d} + k\frac{qQ_2}{d} = kq(\frac{Q_1+Q_2}{d})$

Final kinetic energy due to motion = 0.5·m·v²

Final electric potential energy = $k\frac{qQ_1}{a} + k\frac{qQ_2}{2d-a} = kq(\frac{Q_1}{a}+\frac{ Q_2}{2d-a})$

From the energy conservation principle we have

$0+ kq(\frac{Q_1+Q_2}{d})=0.5mv^2+ kq(\frac{Q_1}{a}+\frac{ Q_2}{2d-a})$

Solving for v gives

$v=\sqrt{\frac{kq(\frac{Q_1+Q_2}{d})- kq(\frac{Q_1}{a}+\frac{ Q_2}{2d-a})}{0.5m}}$

where k = 9.0×10⁹ and m = 9.109×10⁻³¹ kg

gives v =7528188.32769 m/s or 7.53×10⁶ m/s

$v_{final}$ = 7.53×10⁶ m/s

6 0

4 years ago

Que relación encontramos entre el modelo atomico de borh y la tabla periódica

mash [69]

Answer:

Explanation:

3 0

3 years ago

How do you balance this equation Mg+ O2= MgO

Anuta_ua [19.1K]

Answer:

2 Mg(s) + O2(g) → 2 MgO(s)

As magnesium (Mg) has a valency of +2, and oxygen (O) has a valency of -2, the ratio would be 1:1, and magnesium oxide would be represented as MgO. It is insoluble in water, hence it has the subscript as a solid, represented by (s). In order to use up the diatomic oxygen (O2), there needs to be two moles of magnesium (2Mg) on the reactant side. This would produce 2 moles of MgO on the product side.

Explanation:

8 0

4 years ago

A ball traveling with an initial momentum of 5.1 kgm/s bounces off a wall and comes back in the opposite direction with a moment

liubo4ka [24]

Answer:

-9.4 kg m/s

Explanation:

Change in momentum = final momentum − initial momentum

Δp = p − p₀

Δp = -4.3 kg m/s − 5.1 kg m/s

Δp = -9.4 kg m/s

Impulse = change in momentum

J = Δp

J = -9.4 kg m/s

8 0

4 years ago

calculate the initial velocity of an object displaced 33 meters while accelerating 8 m/s^2 to a final velocity of 68 m/s how do

Grace [21]

Use the equation

${v_f}^2-{v_i}^2=2a\Delta x$

The final velocity $v_f$ is 68 m/s, the acceleration $a$ is 8 m/s^2, and the net displacement $\Delta x$ is 33 m, so you can solve for the initial velocity $v_i$ :

$\left(68\,\dfrac{\mathrm m}{\mathrm s}\right)^2-{v_i}^2=2\left(8\,\dfrac{\mathrm m}{\mathrm s^2}\right)(33\,\mathrm m)$

${v_i}^2=4096\,\dfrac{\mathrm m^2}{\mathrm s^2}$

$v_i=64\,\dfrac{\mathrm m}{\mathrm s}$

8 0

3 years ago