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Daniel [21]
3 years ago
15

Please help me I promise will mark u brainest

Physics
1 answer:
zimovet [89]3 years ago
3 0

Answer:

Point A

Explanation:

There are 3 states of equilibrium, which are as follows:

1. Stable Equilibrium

2. Unstable Equilibrium

3. Neutral Equilibrium

<u>1. Stable Equilibrium:</u>

A body is said to be in stable equilibrium, if it comes back to its original position, when it is slightly  displaced. In this case the center of mass of the body is raised up as compared to the initial position.

Example: A book lying on a table, a map hanging on the wall, a stone suspended by a spring.

<u>2. Unstable Equilibrium: </u>

A body is said to be in unstable equilibrium if it does not come back to its original position when it is  slightly displaced. In this case the center of mass of the body is lowered, as compared to the initial position.

Example: A vertical standing pencil, a stick balanced on finger, a funnel resting on its pointed end.

<u>3. Neutral Equilibrium: </u>

A body is said to be in neutral equilibrium, if on being slightly displaced it does not come back to its  original position but occupies a new position similar to its original position. In this case the center of mass of the body remains at same height.

Example: A spherical ball on floor, a cone resting in horizontal position.

So, it is clear from the figure that when we will remove displacement the bus will come back to its original position. Therefore, this is the case of stable equilibrium.

So, the center of mass must have raised up. The original center of mass of the bus must be in the center. So, now the center of mass should have moved above center of bus, vertically.

<u>Therefore, the center of mass of the bus is at point A</u>  

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Two carts on a straight track collide head on. The first cart was moving at 3.6 m/s in the positive x direction and the second w
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vf₁  = -7.2 m/s :  The first car moves in the negative x direction after the collision.

Explanation:

Theory of collisions  

Linear momentum is a vector magnitude (same direction of the velocity) and its magnitude is calculated like this:  

p=m*v  

where  

p:Linear momentum  

m: mass  

v:velocity  

There are 3 cases of collisions : elastic, inelastic and plastic.  

For the three cases the total linear momentum quantity is conserved:  

P₀ = Pf   Formula (1)  

P₀ :Initial linear momentum quantity  

Pf : Final linear momentum quantity  

Data

m₁ = m kg : mass of the first car

m₂= 5m kg : mass of the second car

v₀₁ = 3.6 m/s : Initial velocity of m₁  , to the +x axis :

v₀₂= -2.4 m/s m/s : Initial velocity of m₂ ,  to the -x axis

vf₂= -0.24 m/s m/s : Final velocity of m₂ ,  to the -x axis

Problem development

We appy the formula (1):

P₀ = Pf  

m₁*v₀₁ + m₂*v₀₂ = m₁*vf₁ + m₂*vf₂  

We assume that the first car moves in the positive x direction after the collision., so, the sign of the final speeds is positive:

(m)*( 3.6) + (5m)*( -2.4) = (m)*vf₁ +(5m)*(- 0.24)

3.6m  - 12m=  m*vf₁ - 1.2m

We divided by m both sides of the equation

3.6 - 12= vf₁ -1.2

3.6 - 12 +1.2 = vf₁

-7.2  = vf₁

vf₁  = -7.2 m/s  : The first car moves in the negative x direction after the collision.

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