Que relación encontramos entre el modelo atomico de borh y la tabla periódica

A free body diagram of a brick on an inclined plane is shown below. What is the mechanical advantage of the inclined plane?

Norma-Jean [14]

Answer:

#See solution for details.

Explanation:

-Mechanical advantage is the ratio of input force to an output force.

-Let the length of the inclined plane be x and the height be y.

-The mechanical advantage is calculated as:

$M_{advantage}=\frac{x}{y}$

Hence, the inclined plane increases the force being exerted by $\frac{x}{y}$ times.

5 0

3 years ago

Which part of the electromagnetic spectrum has a higher frequency than ultraviolet light

bezimeni [28]

X-rays and gamma rays are kept up there.

8 0

2 years ago

If the range of the projectile is 4.3 m, the time-of-flight is T = 0.829 s, and air resistance is negligible, determine the foll

ankoles [38]

Answer

given,

range of the projectile = 4.3 m

time of flight = T = 0.829 s

$v =\dfrac{d}{T}$

$v =\dfrac{4.3}{0.829}$

v = 5.19 m/s

vertical component of velocity of projectile

v_y = gt'

$v_y = 9.8 \times {\dfrac{T}{2}}$

$v_y = 9.8 \times {\dfrac{0.829}{2}}$

$v_y =4.06\ m/s$

a) Launch angle

$\theta = tan^{-1}(\dfrac{v_y}{v})$

$\theta = tan^{-1}(\dfrac{4.06}{5.19})$

θ = 38°

b) initial speed of projectile

$v = \sqrt{v_x^2 + v_y^2}$

$v = \sqrt{5.19^2 + 4.06^2}$

v = 6.59 m/s

c) maximum height reached by the projectile

$y_{max}=v_{avg}t'$

$y_{max}=\dfrac{1}{2}v_y\dfrac{T}{2}$

$y_{max}=\dfrac{1}{2}\times(g\dfrac{T}{2})\times\dfrac{T}{2}$

$y_{max}=\dfrac{gT^2}{8}$

7 0

3 years ago

9) If a wave has a speed of 362 m/s and a period of 4.17 s, what is its wavelength?

kakasveta [241]

Answer:

Option B (1.51 m)

Explanation:

U 2 can help me by marking as brainliest........

5 0

1 year ago

Read 2 more answers

Four pairs of objects have the masses as described below, along with the distances between

lord [1]

Answer:

<h2>Mass of 1 Kg and 2 Kg, 1 meters apart.</h2>

Explanation:

The gravitational force is defined as

$F=G\frac{m_{1} m_{2} }{r^{2} }$

By definition, the gravitational force depends directly on the product of the masses and indirectly on the distance between the masses, which means the further they are, the less gravitational force would be. And, the greater the masses, the greater the gravitational force.

Among the options, the pair that would have the greatest gravitational force is Mass of 1 Kg and 2 Kg, with 1 meter between them.

Notice that the last choice includes the same masses but with a greater distance between them, that means it would be a weaker graviational force.

Therefore, the right answer is the second choice.

7 0

3 years ago