1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alexus [3.1K]
4 years ago
6

An object is 30.0 cm to the left of a convex lens with a focal length of +8.0 cm. Draw a ray diagram of the setup showing the lo

cation of the image. Calculate the distance of the image from the lens. Is the image upright or inverted?

Physics
1 answer:
Ostrovityanka [42]4 years ago
4 0
The distance should be 11 cm and the image will be inverted (and smaller)
I used the Lens Equation:
\frac{1}{obj.}+ \frac{1}{im.}  = \frac{1}{f}
Where:
obj. is the distance of the object
im. is the distance of the image
f is the focal length

You might be interested in
Is NaCH an element? Why or why not?
amm1812
<span>NaCH is not an element, it is a compound. An element can be found and identified on the periodic table to elements. A compound is a combination of two of more elements. NaCH is composed of three elements: Na (sodium), C (carbon) and H (hydrogen), making it a compound.</span>
3 0
3 years ago
Why do you think the sickle cell allele is still common in tropical regions?
Ugo [173]
Sickle-cell disease is common in tropical and sub-tropical regions because being a carrier, carrying a single sickle-cell mutation (sickle cell trait), affords some resistance to malaria.
8 0
3 years ago
The heat from the bonfire is transferred to the students hands through the process of???
Allisa [31]
I believe it is Convection, then again I'm not in college.
3 0
3 years ago
Read 2 more answers
Whyy is my computer talking to me
PolarNik [594]

Answer:

good question, did you press any certain buttons?

Explanation:

4 0
3 years ago
Read 2 more answers
A rare butterfly (0.01 kg) is slowly flapping its wings and moving across a road. An unsuspecting driver in a large car (1000 kg
aliya0001 [1]

Both the butterfly and the large car will have equal forces but in opposite direction.

<h3>Newton's third law of motion</h3>

Newton's third law of motion states that action and reaction are equal and opposite. That is, the force exerted on an object is equal to the reaction experienced by the object.

Fa = - Fb

where;

  • Fa is the force exerted by the large car
  • Fb is the force of the butterfly

Thus, both the butterfly and the large car will have equal forces but in opposite direction.

Learn more about Newton's third law of motion here: brainly.com/question/25998091

#SPJ1

8 0
2 years ago
Other questions:
  • 13. A diver swims to a depth of 3.2 m in a freshwater lake. What is the increase in the force pushing in on her eardrum, compare
    10·1 answer
  • Can I see the work for number 55
    15·1 answer
  • Consider a bicycle wheel to be a ring of radius 30 cm and mass 1.5 kg. Neglect the mass of the axle and sprocket. If a force of
    9·1 answer
  • In general it is best to conceptualize vectors as arrows in space, and then to make calculations with them using their component
    12·1 answer
  • A sphere of radius R has charge Q.The electric field strength at distance r &gt; R is E intial. What is the ratio E of the final
    7·1 answer
  • An astronaut is being tested in a centrifuge. The centrifuge has a radius of 11.0 m and, in starting, rotates according to θ = 0
    13·1 answer
  • Three forces F1, F2, and F3 act on an object. Find the force (F2) needed to produce equilibrium if F1 is 786.0 N at 105.0° and F
    15·1 answer
  • Guys this is urgent and I don’t know please help me I will mark brainliest!
    12·1 answer
  • In one or two sentences make and justify a claim about two aspects of the picture that illustrate behaviors of light.
    9·1 answer
  • In astronomy, distances are often expressed in light-years. One light-year is the distance traveled by light in one year. If the
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!