Acceleration = (change in velocity ( final speed - starting speed))/ (time)
Acceleration = (18-30)/10.5
Acceleration = -12/10.5
Acceleration = -1.14 m/s^2
Distance = 30m/s x 10.5s + 1/2(1.14)(10.5)^2
Distance = 252.2 meters
Answer:
Vr = 3.24m/s
The boat is going 3.24m/s relative to the bank of the river.
Explanation:
The relative speed of the boat to the bank Vr is the resultant of speed of boat relative to the water Vb and the speed of boat as a result of the water current or wind Vw
Vr = √(Vb^2 + Vw^2) .....1
Given;
Vb = 2.6m/s
Vw = distance downstream/time = 690m/355s
Vw = 1.94m/s
From equation 1 above; substituting the values
Vr = √(2.6^2 + 1.94^2)
Vr = 3.24m/s
The boat is going 3.24m/s relative to the bank of the river.
Ball 1 Has uchanging motion because it continually goes up no matter what. Ball 2 has no motion. And ball 3 changing motion because it goes from not moving to moving. Hope this helps
To solve this problem we will apply the concept related to the amplitude and the Doppler effect. The difference between the maximum and minimum frequency detected by the microphone would be given by the mathematical function

Here,
= Source Frequency
= Speed of microphone
v = Speed sound

Maximum speed of the microphone is



Now the amplitude is

Here T means the Period, then

A= 0.2605m
Therefore the amplitude of the simple harmonic motion is 0.2605m
Answer:
a) Energy stored in the capacitor, 
b) Q = 45 µC
c) C' = 1.5 μF
d) 
Explanation:
Capacitance, C = 1 µF
Charge on the plates, Q = 45 µC
a) Energy stored in the capacitor is given by the formula:

b) The charge on the plates of the capacitor will not change
It will still remains, Q = 45 µC
c) Electric field is non zero over (1-1/3) = 2/3 of d
From the relation V = Ed,
The voltage has changed by a factor of 2/3
Since the capacitance is given as C = Q/V
The new capacitance with the conductor in place, C' = (3/2) C
C' = (3/2) * 1μF
C' = 1.5 μF
d) Energy stored in the capacitor with the conductor in place
