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zhuklara [117]
3 years ago
5

Which of the materials would be able to scratch Quartz

Physics
1 answer:
Lelechka [254]3 years ago
7 0
<span>anything harder than mohs scale 7 so eg Topaz, Corundum and diamond representing mohs scale 8 9 and 10 respectively.</span>
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The dentisty of an object relies on both the _________ of the object.
Daniel [21]

Answer:

Density is determined by an object's mass and volume.

Explanation:

If two objects take up the same volume, but one has more mass, then it also has a higher density.

7 0
2 years ago
Aluminium,metal,glass,and paper:
Travka [436]

Aluminum metal is a good example of conductor of electricity while glass and paper are good example of insulators.

<h3>What is a conductor?</h3>

A conductor is material that allows easy passage of electric current through the.

<h3>Examples of conductors</h3>

All metals are good examples conductors. such as aluminum, iron, silver, etc.

<h3>What is a non conductor?</h3>

A  non conductor or insulator is a material which does not allow easy passage of electric current through them.

<h3>Examples of insulators</h3>
  • glass
  • paper
  • wood, etc

Thus, aluminum metal is a good example of conductor of electricity while glass and paper are good example of insulators.

The complete question is below:

aluminium,metal,glass,and paper, are examples of what?

Learn more about conductors here: brainly.com/question/24154868

#SPJ1

7 0
2 years ago
May I get some help please?
ziro4ka [17]
Arrows point away from both north and south.
7 0
3 years ago
A spring has a spring constant of 330 n/m. how far is the spring compressed when 150 newtons of force are used?
pishuonlain [190]

Answer:

I think its B

Explanation:

5 0
3 years ago
A fixed 11.2-cm-diameter wire coil is perpendicular to a magnetic field 0.53 T pointing up. In 0.10 s , the field is changed to
Karolina [17]

Answer:

The average induced emf in the coil is 0.0286 V

Explanation:

Given;

diameter of the wire, d = 11.2 cm = 0.112 m

initial magnetic field, B₁ = 0.53 T

final magnetic field, B₂ = 0.24 T

time of change in magnetic field, t = 0.1 s

The induced emf in the coil is calculated as;

E = A(dB)/dt

where;

A is area of the coil = πr²

r is the radius of the wire coil = 0.112m / 2 = 0.056 m

A = π(0.056)²

A = 0.00985 m²

E = -0.00985(B₂-B₁)/t

E = 0.00985(B₁-B₂)/t

E = 0.00985(0.53 - 0.24)/0.1

E = 0.00985 (0.29)/ 0.1

E = 0.0286 V

Therefore, the average induced emf in the coil is 0.0286 V

3 0
3 years ago
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