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mamaluj [8]
4 years ago
6

How much work is done if a box weighing 28 newtons is carrird up a ladder for a distance of 2m

Physics
1 answer:
Zanzabum4 years ago
4 0
14 joules is the answer.
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Find the final velocity of a 40 kg skateboarder traveling at an initial velocity of 10 m/s that moves up a hill from a height of
slavikrds [6]

Answer:

vf = 0

Explanation:

Since the initial height hi = 0, we can rewrite the energy equation as

vf^2 = vi^2 - 2ghf = (10 m/s)^2 - 2(10 m/s^2)(5 m) = 0

Therefore, his final velocity vf is

vf = 0

3 0
3 years ago
a 45kg boy is holding a 12kg pumpkin while standing on ice skates on a smooth frozen pond. the boy tosses the pumpkin with a hor
irga5000 [103]
Let's split the problem into two parts, and let's solve it by using conservation of momentum.

1) Let's analyze the moment when the boy tosses the pumpkin. Before this moment, the boy is standing with the pumpkin, so with speed v=0 and therefore the total momentum of the system (boy+pumpkin) is zero.
After he tosses the pumpkin, the boy will start to move with speed v_b and the pumpkin starts to move with speed v_p=2.8 m/s. The momentum of the boy is m_b v_b (with m_b =45 kg being the mass of the boy), while the momentum of the pumpkin is m_p v_p (where m_p=12 kg is the mass of the pumpkin). Since the total momentum must be equal to zero (because the total momentum cannot change), then we can write
m_b v_b + m_p v_p =0
From which we find
v_b = - \frac{m_p v_p}{m_b}=- \frac{(12 kg)(2.8 m/s)}{45 kg} =-0.75 m/s
and this is the speed of the boy, and the negative sign means he's moving in the opposite direction of the pumpkin.

2) Now let's focus on the entire system (boy+pumpkin+girl). Initially, the total momentum of this system is zero, because both the boy (holding the pumpkin) and the girl are still. So, the total momentum after the girl catches the pumpkin must be still zero.
After this moment, the boy has a momentum of m_b v_b, while the girl has momentum (m_g+m_p)v_g where m_g=37 kg is the girl mass v_g is the girl speed. Here we use m_g+m_p because the girl is holding the pumpkin now. Therefore, the conservation of momentum becomes
m_bv_b + (m_g+m_p)v_g =0
and so
v_g = - \frac{m_b v_b}{m_g+m_p} =- \frac{(45 kg)(-0.75 m/s)}{37 kg+12 kg} =0.69 m/s
and this is the girl's speed, with positive sign so with same direction of the pumpkin initial direction.
6 0
4 years ago
Why do we need to take care of the surface water/groundwater?
ANEK [815]

Answer:

sghskm

rohit zimheisbwhx

3 0
3 years ago
Read 2 more answers
The gravity tractor, is a proposed spacecraft that will fly close to an asteroid whose trajectory threatens to impact the Earth.
Crazy boy [7]

Answer:

F_g=461lb_f

Explanation:

First calculate the mass of the asteroid. To do so, you need to find the volume and know the density of iron.

If r = d/2 = 645ft, then:

V = \frac{4}{3} \pi r^3

V = \frac{4}{3} \pi r^3\\V = 1.124\times10^{9}ft^3\delta_{iron}=m/V=491lb/ft^3m=V\times\delta=5.519\times10^{11}lb

In order to find force, use Newton's universal law of gravitation:

F_g=G\frac{m_1m_2}{d^2}

Where,

G= the gravitational constant:

G= 1.068846 \times10^{-9} ft^3 lb^{-1} s^{-2}

F_g=461lb_f

4 0
3 years ago
A 75 kg skydiver can be modeled as a rectangular "box" with dimensions 20 cm * 40 cm * 180 cm. what is his terminal speed if he
Zina [86]

Terminal speed=136.7 m/s

the formula for the terminal speed is given by :

V= \sqrt{\frac{2 mg}{\rho a C}}

m= mass=75 kg

a= area=0.2 x 0.4=0.08 m²

ρ= density of air=1.23 kg/m³

C= drag constant =0.8

so V= \sqrt{\frac{2 *75*9.8}{1.23*0.08*0.8}}

v= 136.7 m/s

4 0
3 years ago
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