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kati45 [8]
2 years ago
8

A frequently quoted rule of thumb in aircraft design is that wings should produce about 1000 n of lift per square meter of wing.

(the fact that a wing has a top and bottom surface does not double its area.)
Physics
1 answer:
muminat2 years ago
7 0

Answer:

Correct. The lift is directly related to the area of the wing.

Explanation:

The bigger the area of the wing, the bigger the lift will be. But there is a catch: the drag will also be bigger. The denser the air is, more lift and more drag you'll find. At low altitudes, air has more pressure. The higher the pressure is, more lift and drag you'll find. Cold air has more pressure than hot air. Therefore, it's easier for an airplane to takeoff at low altitudes and cold air. But given that drag is also bigger at low altitudes, airplanes tend to have their flight cruises at higher altitudes where there is less lift but there is also less drag as less drag is desirable for saving fuel and flying faster.

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when a substance such as ice melts, its temperature increases. desrcibe what happens to the arrangment of water molecules as the
trasher [3.6K]

Explanation:

The water molecules begins to leave their fixed position and begins to move as the temperature increases.

When ice melts, it undergoes a state change from solid to liquid and with increasing temperature becomes a gas.

  • The basis for this is the increasing movement of the molecules of the water as it transitions from one phase to another.
  • In the ice, the molecules are locked and fixed in the lattice
  • As the temperature increases, the average kinetic energy of the particles rises.
  • This makes the structure of the ice to collapse and forms liquids.
  • By the virtue of this, they flow and move over one another
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If a circle was flattened by pushing down on it, it would most likely form into the shape of an(1) ___ which has(2)___focal poin
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B. 2
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3 years ago
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Yosef is playing with different kinds of rubber bands. Some are very narrow and some are quite wide. Yosef is curious about the
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Answer:

He could have many different hypothesis, but here is one.

Explanation:

If rubber bands are wider, then the rubber bands will stretch further, because the wider a rubber band is the stronger it is.

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A 20.0 μf capacitor is charged to a potential difference of 850 v. the terminals of the charged capacitor are then connected to
liberstina [14]
  • (a) Q = 1.70\times 10^{-2}\;\text{C};
  • (b) V_\text{final} = 5.31\times 10^{2}\;\text{V};
  • (c) E_\text{final} = 4.52\;\text{J};
  • (d) \Delta E = 2.82\;\text{J}.

All four values are in 3 sig. fig.

<h3>Explanation</h3>

(a)

Q = C\cdot V = 20.0\times 10^{-6} \times 850\;\text{V} = 1.70\times 10^{-2}\;\text{J}.

(b)

Sum of the final charge on the two capacitors should be the same as the sum of the initial charge. Voltage of the two capacitors should be the same. That is:

C_1\cdot V_\text{final} +C_2 \cdot V_\text{final} = C_1\cdot V_\text{initial};

(C_1+C_2)\cdot V_\text{final} = C_1\cdot V_\text{initial};

\displaystyle V_\text{final} = \frac{C_1}{C_1+C_2}\cdot V_\text{initial}\\\phantom{V_\text{final}} = \frac{20.0\;\mu\text{F}}{20.0\;\mu\text{F} + 12.0\;\mu\text{F}} \times 850\;\text{V}\\\phantom{V_\text{final}} =531\;\text{V}.

(c)

\displaystyle E = \frac{1}{2}\cdot C\cdot V^{2}.

\displaystyle E_\text{final} = \frac{1}{2} (C_1 + C_2) \cdot {V_\text{final}}^{2} \\\phantom{E_\text{final}} = \frac{1}{2} \times (20.0\times 10^{-6} + 12.0\times 10^{-6}) \times 531.25\\\phantom{E_\text{final}} = 4.52\;\text{J}.

(d)

Initial energy of the system, which is the same as the initial energy in the 20.0\;\mu\text{F} capacitor:

\displaystyle E_\text{initial} = \frac{1}{2} \times 20.0\times 10^{-6} \times 850^{2} = 7.225\;\text{J}.

Change in energy:

\Delta E = 7.225\;\text{J} - 4.516\;\text{J} = 2.70\;\text{J}.

4 0
3 years ago
A box is pushed horizontally with constant speed across a rough horizontal surface. Which of the following must be true?
Pavel [41]
D

Because if an object is moving at a constant speed the force of friction must equal the applied (horizontal) force, and for it to be accelerating or decelerating, the force of friction and the applied force must be unequal
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