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2 years ago

What is the velocity of a jet that travels 785 m [W] in 2.39 s?

Physics

1 answer:

Cerrena [4.2K]2 years ago

7 0

Answer:

v = 328.4

Explanation:

Data:

Distance (d) = 785 m
Time (t) = 2.39 s
Velocity (v) = ?

Use formula:

$\boxed{v = \frac{d}{t}}$

Replace:

$\boxed{v = \frac{785m}{2.39s}}$

It divides:

$\boxed{v = 328.4\frac{m}{s}}}$

What is the velocity?

The velocity is <u>328.4 meters per second.</u>

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Explanation:

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3 years ago

A mass resting on a horizontal, frictionless surface is attached to one end of a spring; the other end is fixed to a wall. It ta

Tomtit [17]

Answer:

(a) 185 N/m

(b) 3.083 kg

Explanation:

(a)

Using,

E = 1/2ke²....................... Equation 1

Where E = work done to compress the spring, k = spring constant of the spring, e = compression of the spring.

make k the subject of the equation

k = 2E/e²............... Equation 2

Given: E = 3.7 J, e = 0.20 m

Substitute into equation 2

k = 2(3.7)/0.2²

k = 185 N/m.

(b)

Using,

F = ma.............. Equation 2

Where F = force applied to the spring, m = mass attached to the spring, a = acceleration of the spring.

But from hook's law,

F = ke................. Equation 3

substitute equation 3 into equation 2

ke = ma

make m the subject of the equation

m = ke/a................ Equation 4

Given: k = 185 N/m, e = 0.2 m, a = 12 m/s²

Substitute into equation 4

m = 185(0.2)/12

m = 3.083 kg

3 0

2 years ago

Read 2 more answers

Advantages of cutting crops with sickle ? please friends give this answer in easy way....

Eva8 [605]

Answer: The only advantage cutting crops with a sickle is that its very effective for cutting lodged crops.

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3 years ago

A pursuit spacecraft from the planet Tatooine is attempting to catch up with a Trade Federation cruiser. As measured by an obser

Ede4ka [16]

Answer:

0.384c

Explanation:

To find the speed of the pursuit ship relative to the cruiser you use the following relativistic equation:

$u'=\frac{u-v}{1-\frac{uv}{c^2}}$

u': relative speed

u: speed of the pursuit ship = 0.8c

v: speed of the cruiser = 0.6c

c: speed of light

You replace the values of the parameters to obtain u':

$u'=\frac{0.8c-0.6c}{1-\frac{(0.6c)(0.8c)}{c^2}}=0.384c$

Hence, the relative speed is 0.384c

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3 years ago