Answer:
Magnitude of angular acceleration = -3.95 rad/s²
Explanation:
Angular acceleration is the ratio of linear acceleration and radius.
That is
![\texttt{Angular acceleration}=\frac{\texttt{Linear acceleration}}{\texttt{Radius}}\\\\\alpha =\frac{a}{r}](https://tex.z-dn.net/?f=%5Ctexttt%7BAngular%20acceleration%7D%3D%5Cfrac%7B%5Ctexttt%7BLinear%20acceleration%7D%7D%7B%5Ctexttt%7BRadius%7D%7D%5C%5C%5C%5C%5Calpha%20%3D%5Cfrac%7Ba%7D%7Br%7D)
Radius = 72 cm = 0.72 m
Linear acceleration is rate of change of velocity.
![a=\frac{11.7-26.5}{5.2}=-2.85m/s^2](https://tex.z-dn.net/?f=a%3D%5Cfrac%7B11.7-26.5%7D%7B5.2%7D%3D-2.85m%2Fs%5E2)
Angular acceleration
![\alpha =\frac{a}{r}=\frac{-2.85}{0.72}=-3.95rad/s^2](https://tex.z-dn.net/?f=%5Calpha%20%3D%5Cfrac%7Ba%7D%7Br%7D%3D%5Cfrac%7B-2.85%7D%7B0.72%7D%3D-3.95rad%2Fs%5E2)
Angular acceleration = -3.95 rad/s²
Magnitude = 3.95 rad/s²
Answer:
KE=800,000
Explanation:
The formula for kinetic energy is KE=1/2mv^2 or Kinetic Energy= 0.5*mass*velocity^2
so 1000 is the mass and 40 is the velocity
KE=0.5*1000*40^2
KE=0.5*1,000*1,600
KE=800,000 Joules
Answer:
i think D I hope this helps!!!!
Answer:
Hello your question is incomplete hence I will give you a general answer on how A van de Graaff generator works
answer :
If the electrons falls through a PD of 150mV the electron will gain energy of 150MeV
Explanation:
when a Van de Graff generator is used to accelerate an electron through a PD ( potential difference ) of any value the particle ( electron ) the electron will gain energy ( eV ) which is is equivalent in value of the PD it accelerated through
hence if the electrons falls through a PD of 150mV the electron will gain energy of 150MeV
Answer:
Efficiency of a machine is how well the machine works and what the machine is capable of doing.
Mechanical advantage=Load/Effort.
720/180=4