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Scrat [10]
3 years ago
11

How often should muscle strengthening activities be performed?

Physics
2 answers:
nevsk [136]3 years ago
8 0

Answer:

B-Once a week

Explanation:

You answer is B-Once a week

LekaFEV [45]3 years ago
3 0

Answer:

once a week

Explanation:

once a week so answer B

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In some cases, neither of the two equations in the system will contain a variable with a coefficient of 1, so we must take a fur
Margaret [11]

Answer:

D = -4/7 = - 0.57

C = 17/7 = 2.43

Explanation:

We have the following two equations:

3C + 4D = 5\ --------------- eqn (1)\\2C + 5D = 2\ --------------- eqn (2)

First, we isolate C from equation (2):

2C + 5D = 2\\2C = 2 - 5D\\C = \frac{2 - 5D}{2}\ -------------- eqn(3)

using this value of C from equation (3) in equation (1):

3(\frac{2-5D}{2}) + 4D = 5\\\\\frac{6-15D}{2} + 4D = 5\\\\\frac{6-15D+8D}{2} = 5\\\\6-7D = (5)(2)\\7D = 6-10\\\\D = -\frac{4}{7}

<u>D = - 0.57</u>

Put this value in equation (3), we get:

C = \frac{2-(5)(\frac{-4}{7} )}{2}\\\\C = \frac{\frac{14+20}{7}}{2}\\\\C = \frac{34}{(7)(2)}\\\\C =  \frac{17}{7}\\

<u>C = 2.43</u>

5 0
3 years ago
what is the period of a sound wave whose wavelength is 20.0m? use values from the book and show all of your work
Lera25 [3.4K]
The wavelength of a sound wave is related to its frequency by the relationship:
f= \frac{v}{\lambda}
where
f is the frequency
v is the speed of the wave
\lambda is the wavelength

The wave in our problem has wavelength of \lambda=20.0 m and speed of v=343 m/s (this is the speed of sound in air), therefore its frequency is
f= \frac{343 m/s}{20.0 m}=17.15 Hz

And the period of the wave is equal to the reciprocal of its frequency:
T= \frac{1}{f}= \frac{1}{17.15 Hz}=0.058 s
5 0
4 years ago
Why is the sky blue in colour?​
Svetllana [295]

\huge\mathrm{Answer࿐}

Our Atmosphere is full of freely subtended particles, and when light from sun strikes the particles then scattering occurs, in which blue colour is most scattered and hence causing Sky to appear blue .

Hope it helps !!

_____________________________

\mathrm{ \#TeeNForeveR}

3 0
3 years ago
Read 2 more answers
A 2.0 m conductor is formed into a square and placed in the horizontal A magnetic field is oriented above the horizontal with a
pashok25 [27]

Answer:

<h3>4.0Wb/m²</h3>

Explanation:

Magnetic flux Ф is expressed using the formula;

Ф = BA

B is magnetic field

A is the area of the square conductor

Given

B = 1.0T

A =L²

Area A = 2.0² = 4.0m²

Get the magnetic flux

Ф = 1.0 * 4.0m²

Ф = 4.0Wb/m²

Hence the magnetic flux through the conductor is 4.0Wb/m²

8 0
3 years ago
a length of wire is cut into five equal pieces. the five pieces are then connected in parallel, with the resulting resistance be
Natali [406]
The equivalent resistance of n resistors connected in parallel is given by
\frac{1}{R_{eq}} =  \frac{1}{R_1}+ \frac{1}{R_2}+...+ \frac{1}{R_n} (1)

In our problem, the resulting resistance of the 5 pieces connected in parallel is R_{Eq}=2.00 \Omega, and since the 5 pieces are identical, their resistance R is identical, so we can rewrite (1) as
\frac{1}{R_{Eq} }= \frac{1}{2 \Omega}= \frac{1}{R}+ \frac{1}{R}   + \frac{1}{R}   + \frac{1}{R}   + \frac{1}{R}   =  \frac{5}{R}
From which we find R= 5 \cdot 2 \Omega = 10 \Omega.

So, each piece of wire has a resistance of 10 \Omega. Before the wire was cut, the five pieces were connected as they were in series. The equivalent resistance of a series of n resistors is given by
R_{Eq}=R_1 + R_2 + ...+R_n
So if we apply it at our case, we have
R_{eq}=R+R+R+R+R=5 R= 5\cdot 10 \Omega= 50 \Omega

therefore, the resistance of the original wire was 50 \Omega.
5 0
3 years ago
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