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Lubov Fominskaja [6]
2 years ago
10

What is the theory of plate tectonics? Question 15 options: A.the theory that earth's surface consists of separate plates that m

ove and interact, producing geologic features and events
B.the theory that earth's surface is one large plate that produces geological features and events

C.the theory that states that the continents were once connected in one large landmass and have since moved apart

D. the theory that earthquakes and volcanoes cause plates on the earth's surface to move
Physics
2 answers:
ollegr [7]2 years ago
8 0

Answer:

A is the answer to your question! hoped this help

vazorg [7]2 years ago
3 0

Answer: A

Explanation:

A.the theory that earth's surface consists of separate plates that move and interact, producing geologic features and events

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We want to design a cylindrical vacuum capacitor, with a given radius a for the outer cylindrical shell, that will be able to st
anastassius [24]

Solution :

a). Using Gauss's law :

  $E=\frac{Q}{4 \pi \epsilon_0r^2}$  ,    $b    .........(1)

Let $E=E_0,\ r=b$ in equation (1)

Therefore, $Q=4 \pi \epsilon_0b^2E_0$  .............(2)

$V_b-V_a = \int^a_b \vec E. d\vec l$

             $=\int^a_b E \ dx$

            $=\frac{Q}{4 \pi \epsilon_0} \int^a_b \frac{1}{x^2} \ dx$

            $=\frac{Q(a-b)}{4 \pi \epsilon_0 a b}$  ....................(3)

Therefore, $U=\frac{1}{2}Q \Delta V$

                     $=\frac{1}{2}(4 \pi \epsilon_0 b^2 E_0)\left(\frac{Q(a-b)}{4\pi \epsilon_0 a b}\right)$

                     $=\frac{4 \pi \epsilon_0}{2a} \ E^2_0 b^3(a-b)$  .............(4)

Now differentiating the equation (4) w.r.t. 'b', we get

$b=\frac{3}{4}a$  

Thus the radius for the inner cylinder conductor is $b=\frac{3}{4}a$

b). For the energy storage, substitute the radius in (4), we get

$U = 4 \pi\epsilon_0 \frac{27a^3E^2_0}{512}$

This is the amount of energy stored in the conductor.

8 0
3 years ago
What is Newtens first law of motion​
OlgaM077 [116]

Newtons first law states that an object will remain still or in straight line. Until acted upon some force!

4 0
3 years ago
Read 2 more answers
malcom is doing a wheely on his motorcycle and moving at 20 m/s with a momentum of 6000 kg m/s when he lays her down. The mass o
rodikova [14]

Answer:

110 kg

Explanation:

The momentum of the Malcom+motorcycle system is given by:

p=(m+M)v

where

(m+M) is the total mass of the system, with

m = mass of Malcom

M = 190 kg (mass of the motorcycle)

v = 20 m/s velocity

Since we know the momentum:

p = 6000 kg m/s

We can re-arrange the equation to find the mass of Malcom:

m=\frac{p}{v}-M=\frac{6000 kg m/s}{20 m/s}-190 kg=110 kg

3 0
3 years ago
A sample of a radioactive substance is reduced to 1.0 gram after 4 half-lives. Determine the mass of the original sample
luda_lava [24]

After 4 half-lives, there was 1 gram.

1 half-life earlier, after 3 half-lives, there must have been 2 grams.

1 half-life earlier, after 2 half-lives, there must have been 4 grams.

1 half-life earlier, after 1 half-life, there must have been 8 grams.

1 half-life earlier, when it started decaying, there must have been 16 grams. <em>(B) </em>

6 0
3 years ago
A bird carries a 25 g oyster to a height of 11m what is the gravitational potential energy of the oyster
garik1379 [7]

Given data:

Mass of oyster (m) = 25 g,

                              = 0.025 kg            (<em> since 1 Kg = 1000 g)</em>

Height of oyster (h) = 11 m,

determine gravitational potential energy (GPE) = ?

Gravitational potential energy is energy of an object possesses because of its position on the earth. The amount of gravitational potential energy of an object on earth depends on its<em> mass</em> and<em> height </em>from the earth.  

Mathematically,

        GPE = m. g. h <em>Joules</em>

<em>         Where, </em>

<em>               </em>GPE =<em> </em>gravitational potential energy,

<em>         </em>          m = mass of object in Kg,

                  g = gravitational force in m/s²,     g = 9.8 m/s²

                  h = height of the object in meters,

     Now substituting all the values in the equation GPE

           GPE = 0.025 Kg × 9.8 m/s² × 11 m

                   = 2.695 J

Gravitational potential energy of the oyster is 2.695 J


7 0
3 years ago
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