Anyone care to help me with my math?

Mathematics

2 answers:

Anna35 [415]3 years ago

3 0

1=2 -corresponding angle
2+3=180° (linear pair)
1+3=180°

soldi70 [24.7K]3 years ago

3 0

It seems like the other person ansered the question correctly because the answer is 180!!

You might be interested in

Which event has a probability other than 1/2 ?

NNADVOKAT [17]

The answer to this is 4

4 0

3 years ago

Read 2 more answers

A coyote can run up to 43 miles per hour while a rabbit can run up to 35 miles per hour.write two equivalent expression and then

yaroslaw [1]

D=s*t
distaance=speed times time

cd=coyote distance*time=ds*dt
rd=rabbit diatance*time=rs*rt

given
t=6 for all, so dt=rt=6

and ds=43
rs=35

cd=43*6=258miles
rd=35*6=210miles

how much more?
258-210=48

48 more miles

5 0

2 years ago

If f(x) = 9x10 tan−1x, find f '(x).

djverab [1.8K]

Answer:

$\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}$

General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]: $\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle f(x) = 9x^{10} \tan^{-1}(x)$

Step 2: Differentiate

[Function] Derivative Rule [Product Rule]: $\displaystyle f'(x) = \frac{d}{dx}[9x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Rewrite [Derivative Property - Multiplied Constant]: $\displaystyle f'(x) = 9 \frac{d}{dx}[x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Basic Power Rule: $\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Arctrig Derivative: $\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}$