The molarity of the potassium hydroxide required to neutralize 60.0 mL of 0.0100 M H3PO4 is 0.02M.
<h3>How to calculate molarity?</h3>
The molarity of a solution can be calculated using the following formula:
CaVa = CbVb
Where;
- Ca = concentration of acid
- Cb = concentration of base
- Va = volume of acid
- Vb = volume of base
60 × 0.0100 = 30 × Cb
0.6 = 30Cb
Cb = 0.6/30
Cb = 0.02M
Therefore, molarity of the potassium hydroxide required to neutralize 60.0 mL of 0.0100 M H3PO4 is 0.02M.
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First is hydrogen and second is oxygen
Answer:
- The room mantained at a lower temperature will contain more air molecules.
Explanation:
1) Since the two rooms are <em>connected by an open door</em>, you assume pressure equilibrium: the pressure on the two rooms is the same.
2) Since you consider <em>two equal size rooms</em>, both volumes are equal.
3) Assuming ideal gas behavior, pressure (P), temperature (T), volume (V) and number of moles (n) are related by the equation PV = nRT
4) Naming T₁ the lower temperature, T₂ the higher temperature, n₁ the number of moles of air in the room at lower temperature, and n₂ the number of moles of air in the room at higher temperature, you get:
- n₁ T₁ = n₂ T₂, or n₁ / n₂ = T₂ / T₁
5) That means that the amount of molecules (number of moles) is inversely related to the temperature: the higher the temperature the lower the number of moles, and the lower the temperature the greater the number of moles.
Hence, the answer is that <em>the room that contains more air molecules is the room mantained at a lower temperature.</em>