Question

Using equation e=(hcrh)(1n2)=(−2.18×10−18j)(1n2), calculate the energy of an electron in the hydrogen atom when n= 5.

Answer 1

8.72 x 10^(-20)J

Hope this helps!! ( If not sorry!)

Answer 2

The given formula for energy is:

$E = hcR_{H}(\frac{1}{n^{2}})$     (1)

where,

h = planck's constant

c = $\frac{1}{\lambda }$ =$\nu$ (frequency)

n = energy level

Substitute the given value of n and $hcR_{H}$ in formula (1)

$Energy = (-2.18 \times 10^{-18 }J)\times (\frac{1}{5^{2}})$

= $(-2.18 \times 10^{-18 }J)\times (\frac{1}{25})$

= $(-2.18 \times 10^{-18 }J)\times (0.04)$

= $-0.0872 \times 10^{-18 }J$

= $-8.72 \times 10^{-20 }J$

Thus, energy of an electron in the hydrogen atom when n = 5 is $-8.72 \times 10^{-20 }J$