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tresset_1 [31]
3 years ago
14

A wooden artifact from an ancient tomb contains 60% of the carbon-14 that is present in living trees. How long ago was the artif

act made? (The half-life of carbon-14 is 5730 years. Round your decay rate, r, to 6 decimal places. Then round your answer to the nearest whole number.)
Chemistry
1 answer:
noname [10]3 years ago
8 0

Answer:

The age of the sample is 4224 years.

Explanation:

Let the age of the sample be t years old.

Initial mass percentage of carbon-14 in an artifact = 100%

Initial mass of carbon-14 in an artifact = [A_o]

Final mass percentage of carbon-14 in an artifact t years = 60%

Final mass of carbon-14 in an artifact = [A]=0.06[A_o]

Half life of the carbon-14 = t_{1/2}=5730 years

k=\frac{0.693}{t_{1/2}}

[A]=[A_o]\times e^{-kt}

[A]=[A_o]\times e^{-\frac{0.693}{t_{1/2}}\times t}

0.60[A_o]=[A_o]\times e^{-\frac{0.693}{5730 year}\times t}

Solving for t:

t = 4223.71 years ≈ 4224 years

The age of the sample is 4224 years.

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Use the following data to estimate ΔHf° for magnesium fluoride. Mg(s) + F2(g) → MgF2(s) lattice energy −2913 kJ/mol first ioniza
miss Akunina [59]

Answer:

The correct answer is -1085 KJ/mol

Explanation:

To calculate the formation enthalphy of a compound by knowing its lattice energy, you have to draw the Born-Haber cycle step by step until you obtain each element in its gaseous ions. Find attached the correspondent Born-Haber cycle.

In the cycle, Mg(s) is sublimated (ΔHsub= 150 KJ/mol) to Mg(g) and then atoms are ionizated twice (first ionization: ΔH1PI= 735 KJ/mol, second ionization= 1445 KJ/mol) to give the magnesium ions in gaseous state.

By other hand, the covalent bonds in F₂(g) are broken into 2 F(g) (Edis= 154 KJ/mol) and then they are ionizated to give the fluor ions in gaseous state 2 F⁻(g) (2 x ΔHafinity=-328 KJ/mol). The ions together form the solid by lattice energy (ΔElat=-2913 KJ/mol).

The formation enthalphy of MgF₂ is:

ΔHºf= ΔHsub + Edis + ΔH1PI + ΔH2PI + (2 x ΔHaffinity) + ΔElat

ΔHºf= 150 KJ/mol + 154 KJ/mol + 735 KJ/mol + 1445 KJ/mol + (2 x (-328 KJ/mol) + (-2913 KJ/mol).

ΔHºf= -1085 KJ/mol

3 0
3 years ago
What is the density of N2 gas (molar mass: 28 g/mol), at 400 K and 2 atm?
Olenka [21]

Answer:

Density= 1.7g/dm3

Explanation:

Applying

P×M= D×R×T

P= 2atm, Mm= 28, D=? R= 0.082, T= 400K

2×28= D×0.082×400

D= (2×28)/(0.082×400)

D= 1.7g/dm3

7 0
3 years ago
10g of an oxide of copper contains 8.882g of copper. what is empirical formula of the copper oxide
-BARSIC- [3]

Answer:

Mass of copper oxide: 10g

Mass of copper: 8.882g

Mass of oxygen: 1.118g

                                                                <u> Cu</u>               <u>O</u>

                                                              8.882           1.118

Divide by A_{r}                                   8.882÷63.5       1.118÷16

                                                               0.14             0.07

Divide by the lowest number          0.14/0.07       0.07/0.07

                                                                  2                  1

Check the ratio now, Cu has 2 atoms and O has 1 atom .

The formula is Cu_{2} O

4 0
2 years ago
En invierno, nieva en la cordillera.
Serggg [28]
Que es el question que necesitas?
8 0
2 years ago
For the balanced equation shown below, if 84.7 grams of H2S were reacted with 78.4 grams of O2, how many grams of H2O would be p
Klio2033 [76]
The mass  of  water  is  calculated  as   follows

  find  the  moles  of   each  reagent

that   is   moles =   mass/molar  mass

for  H2s  =  84.7/   34=   2.485  moles
      O2  =  78.4  /   32  =  2.45  moles

since    2  moles  of  H2S  react   with  3  moles  of O2  therefore  2.45  moles   of  oxygen  will  be  used  up  therefore  O2  is  the    limiting   reagent   and  H2S  is  in  excess

2H2S  +  3O2  ----->2So2   +  2H2O

by  use  of   mole   ratio  between  O2  and   H20   which  is  3:2  the   moles of  H2O  is  therefore  =  2.45 x2/3= 1.63  moles  of H2O

mass  of H2O  =  moles   x  molar  mass

=  1.63  g  x  18g/mol  =  29.4   g
4 0
3 years ago
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