Answer:
The correct answer is -1085 KJ/mol
Explanation:
To calculate the formation enthalphy of a compound by knowing its lattice energy, you have to draw the Born-Haber cycle step by step until you obtain each element in its gaseous ions. Find attached the correspondent Born-Haber cycle.
In the cycle, Mg(s) is sublimated (ΔHsub= 150 KJ/mol) to Mg(g) and then atoms are ionizated twice (first ionization: ΔH1PI= 735 KJ/mol, second ionization= 1445 KJ/mol) to give the magnesium ions in gaseous state.
By other hand, the covalent bonds in F₂(g) are broken into 2 F(g) (Edis= 154 KJ/mol) and then they are ionizated to give the fluor ions in gaseous state 2 F⁻(g) (2 x ΔHafinity=-328 KJ/mol). The ions together form the solid by lattice energy (ΔElat=-2913 KJ/mol).
The formation enthalphy of MgF₂ is:
ΔHºf= ΔHsub + Edis + ΔH1PI + ΔH2PI + (2 x ΔHaffinity) + ΔElat
ΔHºf= 150 KJ/mol + 154 KJ/mol + 735 KJ/mol + 1445 KJ/mol + (2 x (-328 KJ/mol) + (-2913 KJ/mol).
ΔHºf= -1085 KJ/mol
Answer:
Density= 1.7g/dm3
Explanation:
Applying
P×M= D×R×T
P= 2atm, Mm= 28, D=? R= 0.082, T= 400K
2×28= D×0.082×400
D= (2×28)/(0.082×400)
D= 1.7g/dm3
Answer:
Mass of copper oxide: 10g
Mass of copper: 8.882g
Mass of oxygen: 1.118g
<u> Cu</u> <u>O</u>
8.882 1.118
Divide by
8.882÷63.5 1.118÷16
0.14 0.07
Divide by the lowest number 0.14/0.07 0.07/0.07
2 1
Check the ratio now, Cu has 2 atoms and O has 1 atom .
The formula is 
Que es el question que necesitas?
The mass of water is calculated as follows
find the moles of each reagent
that is moles = mass/molar mass
for H2s = 84.7/ 34= 2.485 moles
O2 = 78.4 / 32 = 2.45 moles
since 2 moles of H2S react with 3 moles of O2 therefore 2.45 moles of oxygen will be used up therefore O2 is the limiting reagent and H2S is in excess
2H2S + 3O2 ----->2So2 + 2H2O
by use of mole ratio between O2 and H20 which is 3:2 the moles of H2O is therefore = 2.45 x2/3= 1.63 moles of H2O
mass of H2O = moles x molar mass
= 1.63 g x 18g/mol = 29.4 g