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3 years ago

What is a gas’s temperature in Celsius when it has a volume of 25 L, 203 mol, 143.5 atm?

Chemistry

1 answer:

slava [35]3 years ago

4 0

To Find :

Gas’s temperature in Celsius when it has a volume of 25 L, 203 mol, 143.5 atm .

Solution :

We know, by ideal gas equation :

$PV =nRT\\\\T = \dfrac{PV}{nR}$

Here, R is universal gas constant and $R = 0.082 \ L \ atm \ mol^{-1} \ K^{1}$

Putting all given values and R in above equation, we get :

$T = \dfrac{PV}{nR}\\\\T = \dfrac{143.5\times 25}{203 \times 0.082}\ K\\\\T = 215.52\ K$

Hence, this is the required solution.

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The question is missing information. Here is the complete question.

A gas at a pressure of 2.0 atm is in a closed container. Indicate the changes (if any) in its volume when the pressure undergoes the following changes at constant temperature and constant amount of gas. Match the words in the left with the column to the appropriate blanks in the sentences on the right. Make certain each sentence is complete before submitting your answer.

1. The pressure increases to 6.0 atm. The volume ________

2. The pressure drops to 0.40 atm. The volume _________

3. The pressure remains at 2.0 atm. The volume _________

Answer: 1. Decreases

2. Increases

3. Does not change

Explanation: According to the Ideal Gas Law, Pressure, Volume and Temperature of an ideal gas is related, as the following: PV = nRT.

In this case, since temperature (T) and amount of gas (n) are constant, the Boyle's Law can be used.

The law states that the volume of a given gas, under the conditios of temperature and amount of it are constant, is inversely proportional to the applied pressure: P₁.V₁ = P₂.V₂

For case 1.)

Initial P (P₁) = 2

Initial V (V₁) = V

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2.V = 0.4V₂

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3 years ago