M=DxV V=M/D
(answer limit etcetcetc)))))
Answer:
part (a) was used to calculate the molar mass of the metal M. In part (c) students proposed an experimental test that could be used to determine if MI 2 is an ionic solid, and then explained how the results of the test supported this claim. Students explained why I 2 is solid at room temperature, but Br 2 is a liquid in part (d). its {c}
Answer:
Both
Explanation:
An industrial chemist most consider must consider both the income earned from production of a chemical and the cost of handling the waste materials created.
A high yield is desirable, because it maximizes income.
A high atom economy is desirable, because it minimizes the amount of waste and therefore the cost of treating it.
Solving part-1 only
#1
KMnO_4
- Transition metal is Manganese (Mn)
#2
Actually it's the oxidation number of Mn
Let's find how?
- x is the oxidation number
#3
- Purple as per the color of potassium permanganate
#4
Answer:
Region one because an area that has contour lines close together means that the area is steep. but in region ones case it has <u>no</u> contour lines meaning the area is flat.