Answer:
0.84kg of gatorade powder
Explanation:
From the question given, we were told that 0.6kg of gatorade powder required 5 gallons of water.
To obtain the mass of gatorade needed for 7 gallons of water, we simply do the following:
0.6kg of gatorade powder required 5 gallons of water.
Therefore, xkg of gatorade powder will require 7 gallons of water i.e
xkg of gatorade powder = (0.6 x 7)/5
xkg of gatorade powder = 0.84kg
Therefore, 0.84kg of gatorade powder will be required.
Answer:
ZnS(s) ⇄ S²⁻(aq) + Zn²⁺(aq)
Explanation:
First, we will write the molecular equation, since it is easier to balance.
2 HBr(aq) + ZnS(s) ⇄ H₂S(aq) + ZnBr₂(aq)
In the full ionic equation we include all ions and molecular species.
2 H⁺(aq) + 2 Br⁻(aq) + ZnS(s) ⇄ 2 H⁺(aq) + S²⁻(aq) + Zn²⁺(aq) + 2 Br⁻(aq)
In the net ionic equation we include only the ions that participate in the reaction and the molecular species.
ZnS(s) ⇄ S²⁻(aq) + Zn²⁺(aq)
12.5 gallons is 47.3 liters
hope that helps
Answer:
2.8 L
Explanation:
From the question given above, the following data were obtained:
Number of mole (n) = 0.109 mole
Pressure (P) = 0.98 atm
Temperature (T) = 307 K
Gas constant (R) = 0.0821 atm.L/Kmol
Volume (V) =?
The volume of the helium gas can be obtained by using the ideal gas equation as follow:
PV = nRT
0.98 × V = 0.109 × 0.0821 × 307
0.98 × V = 2.7473123
Divide both side by 0.98
V = 2.7473123 / 0.98
V = 2.8 L
Thus, the volume of the helium gas is 2.8 L.
Explanation:
Hey there! Down here!
Four effects of heat are :-
- In electric Heaters
- In geysers
- In thermos [ a bottle type used to keep water at its nominal temperature when is was inserted]
- In Micro Oven and OTG's
Five examples of Conductors :-
- Graphite
- Silver
- Copper
- Alumunium
- Steel
Hope it helps :)
