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3 years ago

Here is a list of ingredients for a simple cake:

1 answer:

3 0

So really you only need to answer the first one because you have more than enough og everything. 2×(what)=14 then that will be your answer

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If 400 Joules of work is done in 20 seconds, how much power was generated?

Sonbull [250]

To work this out you do 400÷20=20

5 0

3 years ago

No FILES PLZZ

Bumek [7]

Answer:

Converted to renewable ones

exhausted or depleted

5 0

2 years ago

Read 2 more answers

Methanol (ch3oh), also called methyl alcohol, is the simplest alcohol. it is used as a fuel in race cars and is a potential repl

erica [24]

Answer:

%age Yield = 51.45 %

Solution:

Step 1: Convert Kg into g

68.5 Kg CO = 68500 g CO

8.60 Kg H₂ = 8600 g

Step 2: Find out Limiting reactant;

The Balance Chemical Equation is as follow;

CO + 2 H₂ → CH₃OH

According to Equation,

28 g (1 mol) CO reacts with = 4 g (2 mol) of H₂

So,

68500 g CO will react with = X g of H₂

Solving for X,

X = (68500 g × 4 g) ÷ 28 g

X = 9785 g of H₂

It shows 9785 g H₂ is required to react with 68500 g of CO but we are provided with 8600 g of H₂ which is less than required. Therefore, H₂ is provided in less amount hence, it is a Limiting reagent and will control the yield of products.

Step 3: Calculate Theoretical Yield

According to equation,

4 g (2 mol) H₂ reacts to produce = 32 g (1 mol) Methanol

So,

8600 g H₂ will produce = X g of CH₃OH

Solving for X,

X = (8600 g × 32 g) ÷ 4 g

X = 68800 g of CH₃OH

Step 4: Calculate %age Yield

%age Yield = Actual Yield ÷ Theoretical Yield × 100

Putting Values,

%age Yield = 3.54 × 10⁴ g ÷ 68800 g × 100

%age Yield = 51.45 %

5 0

3 years ago

Calculate the solubility of Mg(OH)2 in water at 25 C. You'll find Ksp data in the ALEKS Data tab. Round your answer to significa

elena-s [515]

Answer:

1.12 × 10⁻⁴ M

Explanation:

Step 1: Write the reaction for the solution of Mg(OH)₂

Mg(OH)₂(s) ⇄ Mg²⁺(aq) + 2 OH⁻(aq)

Step 2: Make an ICE chart

We can relate the solubility product constant (Ksp) with the solubility (S) through an ICE chart.

Mg(OH)₂(s) ⇄ Mg²⁺(aq) + 2 OH⁻(aq)

I 0 0

C +S +2S

E S 2S

The solubility product constant is:

Ksp = 5.61 × 10⁻¹² = [Mg²⁺] × [OH⁻]² = S × (2S)² = 4S³

S = 1.12 × 10⁻⁴ M

8 0

2 years ago

What is the mass of 18.0 mL of honey if its' density is 1.42 g/mL?

BigorU [14]

mass (m) = ? , volume = 18.0 ml , density = 1.42 g/ml .

$density = \frac{mass}{volume} \\ \\ d = \frac{m}{v} \\ \\ mass = density \times volume \\ \\ m = d \times v \\ \\ m = 18 \: ml \times \: 1.42 \: \frac{g}{ml} \\ \\ m = 25.56 \: g$

I hope I helped you^_^

8 0

2 years ago