Answer: 3 <span>moles of water would be produced in present case.
</span>
Reason:
Reaction involved in present case is:
<span> C5H12 + 8O2 </span>→<span> 5CO2 + 6H2O
In above reaction, 1 mole of C5H12 reacts with 8 moles of oxygen to give 6 moles of water.
Thus, 4 moles of oxygen will react with 0.5 mole of C5H12, to generate 3 moles of H2O.</span>
First, we convert the masses into fractions
<span>138 g of benzene = 1.77 moles benzene
91.2 g of heptane = 0.93 moles heptane
Next, calculate the mole fractions
x1 (benzene) = 1.77 / (1.77 + 0.93) = 0.66
x2 (heptane) = 1 - 0.66 = 0.34
</span>The vapor pressure of pure benzene is 322 torr at 40 C.
At the same temperature, the vapor pressure of heptane is 92 torr.
<span>
The partial pressure of benzene is
p1 = 0.66 (322) = 212.52 torr
The partial pressure of heptane is
p2 = 0.34 (92) = 31.28 torr
</span>
Answer:be careful and relax
Explanation:
Answer : The pressure at this new altitude is, 364.2 mmHg
Explanation :
Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

or,

where,
= initial pressure = 760 mmHg
= final pressure = ?
= initial volume = 62.3 L
= final volume = 130 L
Now put all the given values in the above equation, we get:


Thus, the pressure at this new altitude is, 364.2 mmHg
Answer:
A dangerous condition in a nuclear reactor when fuel rods melt is called NUCLEAR MELTDOWN