To start with solving this
problem, let us assume a launch angle of 45 degrees since that gives out the
maximum range for given initial speed. Also assuming that it was launched at
ground level since no initial height was given. Using g = 9.8 m/s^2, the
initial velocity is calculated using the formula:
(v sinθ)^2 = (v0 sinθ)^2
– 2 g d
where v is final
velocity = 0 at the peak, v0 is the initial velocity, d is distance = 11 m
Rearranging to find for
v0: <span>
v0 = sqrt (d * g/ sin(2 θ)) </span>
<span>v0 = 10.383 m/s</span>
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Among the choices the one that is correct about relationship between the readings is letter D which is RC RD
Answer:
216.39 N/m
Explanation:
F = 64.7 N
x = 0.299 m
Plug those values into Hooke's Law:
F = kx
64.7 N = k(0.299 m)
---> k = 216.39 N/m
