Answer:
40 ms¯².
Explanation:
To solve this problem, we shall illustrate the question with a diagram.
The attached photo gives a better understanding of the question.
From the attached photo:
Velocity (v) = 160 ms¯¹
Time (t) = 4 secs.
Acceleration (a) =?
Acceleration (a) = Velocity (v) /time (t)
a = v/t
a = 160/4
a = 40 ms¯²
Therefore, the initial acceleration of the rocket is 40 ms¯².
Answer:
The angle of the incline above horizontal is 17.81 degrees.
Explanation:
Given that,
Mass of the object, m = 4 kg
Acceleration of the object above the incline,
We need to find the angle of the incline above horizontal. The net force acting on the object along the incline is given by :
So, the angle of the incline above horizontal is 17.81 degrees. Hence, this is the required solution.
Answer:
The final pressure of oxygen gas is 8.33 atm.
Explanation:
From the given data
V=26 m^3 or 26000 L
T1=270K
T2=440K
n1=6000 moles
R=0.0821 L.atm/molK
Now from the ideal gas equation
As the options given are not defined in which unit thus the final pressure of oxygen gas is 8.33 atm.
<em>*The options are provided for a different question where </em>