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fomenos
3 years ago
7

A car traveling at 30 m/s drives off a cliff that is 50 meters high? How far away does it land?

Physics
1 answer:
Semenov [28]3 years ago
3 0

Answer:

The maximum range R_{max}= 132. 72 m

Explanation:

Given,

The initial velocity of the car, u = 30 m/s

The height of the cliff, h = 50 m

Let the car drives off the cliff with a horizontal velocity of 30 m/s.

The formula for a projectile that is projected from a height h from the ground is given by the relation

                                R_{max}= \frac{u}{g}\sqrt{u^{2} + 2gh }  m

Where,

                          g - acceleration due to gravity

Substituting the values in the above equation

                   R_{max}= \frac{30}{9.8}\sqrt{30^{2} + 2X9.8X50 }  

                                          = 132.72  m

Hence, the car lands at a distance, R_{max}= 132. 72 m            

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Rufina [12.5K]

Answer:

10 N

Explanation:

Use the equation W=Fd, where W is the work (in joules), F is the force (in newtons), and d is the distance (in meters).'

W=Fd\\50=F(5)\\F=10 N

7 0
2 years ago
The wheel of a stationary exercise bicycle at your gym makes one rotation in 0.670 s. Consider two points on this wheel: Point P
lesya [120]

Answer:

a) For P: v=0.938\frac{m}{s}

For Q: v = 1.876\frac{m}{s}

b) For P:

a_{rad}=8.80\frac{m}{s^{2}}

for Q:

a_{rad}=17.60\frac{m}{s^{2}}

c) As the distance from the axis increases then speed increases too.

Explanation:

a) Assuming constant angular acceleration we can find the angular speed of the wheel dividing the angular displacement θ between time of rotation:

\omega =\frac{\theta}{t}

One rotation is 360 degrees or 2π radians, so θ=2π

\omega =\frac{2\pi}{0.670} =9.38\frac{rad}{s}

Angular acceleration is at every point on the wheel, but speed (tangential speed) is different and depends on the position (R) respect the rotation axis, the equation that relates angular speed and speed is:

v = \omega R

for P:

v = 9.38\frac{rad}{s}*0.1m=0.938\frac{m}{s}

for Q:

v = 9.38\frac{rad}{s}*0.2m=1.876\frac{m}{s}

b) Centripetal acceleration is:

a_{rad}= \frac{v^2}{R}

for P:

a_{rad}= \frac{(0.938)^2}{0.1}=8.80\frac{m}{s^{2}}

for Q:

a_{rad}= \frac{(1.876)^2}{0.2}=17.60\frac{m}{s^{2}}

c) As seen on a) speed and distance from axis is v = \omega R because ω is constant the if R increases then v increases too.

3 0
3 years ago
When lost fluid is not replaced adequately can result
Pani-rosa [81]
When lost fluid is not replaced adequately, dehydration can result.
4 0
3 years ago
If two objects with static charge are attracted what do you know about them?
klemol [59]
They carry opposite charge ( one has negative charge and one has positive charge)
4 0
3 years ago
A racing car on a straight accelerates from 100mph to 316 mph in three seconds what is the acceleration?
omeli [17]

Answer:

72mph/sec

Explanation:

The car goes from 100mph to 316mph in three seconds. Meaning it increases its speed by (316 - 100)mph in three seconds. That is 216 mph increase in three seconds. So, we divide the speed increase by the amount of time the increase occurred over. We get:

216mph / 3sec = 72mph/sec, our final answer

Hope it made sense. I would appreciate Brainliest, but no worries.

8 0
3 years ago
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