Question

A car traveling at 30 m/s drives off a cliff that is 50 meters high? How far away does it land?

Answer 1

Answer:

The maximum range $R_{max}= 132. 72$ m

Explanation:

Given,

The initial velocity of the car, u = 30 m/s

The height of the cliff, h = 50 m

Let the car drives off the cliff with a horizontal velocity of 30 m/s.

The formula for a projectile that is projected from a height h from the ground is given by the relation

                                $R_{max}= \frac{u}{g}\sqrt{u^{2} + 2gh }$  m

Where,

                          g - acceleration due to gravity

Substituting the values in the above equation

                   $R_{max}= \frac{30}{9.8}\sqrt{30^{2} + 2X9.8X50 }$  

                                          = 132.72  m

Hence, the car lands at a distance, $R_{max}= 132. 72$ m