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3 years ago

Volume or intensity of a sound wave is measured by the size of the _________ and reported in decibels.

Physics

2 answers:

zepelin [54]3 years ago

7 0

The answer would be; Amplitude.

Hope that helps! :-)

Lena [83]3 years ago

3 0

Answer:

Amplitude

Explanation:

The intensity (or volume) of a sound wave is proportional to the square of the sound wave:

$I\propto A^2$

where A is the amplitude of the wave.

The amplitude of a sound wave is measured as the maximum displacement of the wave with respect to its equilibrium position.

The intensity is measured in Decibels (dB), which is related to the logarithmic ratio between the power of two different sounds, i.e. the difference in decibels between two sounds is given by

$10 Log (\frac{P_2}{P_1})$

where P1 and P2 are the power of the two sounds.

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What is the value of g

Mariana [72]

It depends on the environment around you ... the number and size of
the masses around you, and your distance from their center of mass.

If you happen to be on the surface of the Earth, then

   g = 9.8 m/s²
   or
   g = 9.8 newton/kilogram .

It's different on other planets. Be sure to look it up
before you leave, so you'll know what to expect.

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4 years ago

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3 years ago

Scientists observe an approaching asteroid that is on a collision course with

nasty-shy [4]

Answer:

The approximate velocity the rocket must have to stop the asteroid completely after the collision is;

C. -324 m/s

Explanation:

The parameters of the asteroid and the rocket are;

The mass of the asteroid, m₁ = 11,000 kg

The initial velocity with which the asteroid is approaching Earth, v₁ = 50 m/s

The mass of the rocket, m₂ = 1700 kg

The initial velocity of the rocket = v₂

The final velocity of the combined asteroid and rocket after the collision, v₃ = 0 m/s

By the law of conservation of linear momentum, we have;

The total initial momentum = The total final momentum

m₁·v₁ + m₂·v₂ = (m₁ + m₂)·v₃

Substituting the known values, we get;

11,000 kg × 50 m/s + 1,700 kg × v₂ = (11,000 kg + 1,700 kg) × 0 m/s

11,000 kg × 50 m/s + 1,700 kg × v₂ = 0

∴ 1,700 kg × v₂ = -11,000 kg × 50 m/s

v₂ = (-11,000 kg × 50 m/s)/(1,700 kg) = -323.529412 m/s ≈ -324 m/s

The approximate initial velocity the jet must have to completely stop the asteroid after the collision is -324 m/s.

3 0

3 years ago

A submarine deep underwater releases a bubble of air. The total pressure at this depth is P. The bubble has diameter, D, and abs

Sunny_sXe [5.5K]

Answer:

P V = n R T ideal gas equation

P2 V2 / P1 V1 = T2 / T1

V2 / V1 = T2 / T1 * P1 / P2 = T2 P1 / (T1 P2)

V2 / V1 = (1.17 T1) / T1 * (P1 / .22 P1) assuming absolute temp as 1.17 P1

V2 / V1 = 1.17 / .22 = 5.32

V = 4/3 pi R^3 = 4/3 pi (D/2)^3 = 4/3 pi D^3 / 8 = pi D^3 / 6

V2 / V1 = D2^3 / D1^3

D2 = (V2 / V1 * D1^3)^1/3

D2 = 5.32^1/3 * D = 1.75 D (D1 = D)

7 0

3 years ago

A ball is thro.d hit the grouvelocity)?

kati45 [8]

Answer:

The velocity of the ball is 3.52 m/s.

Explanation:

A projectile is any object that moves under the influence of gravity and momentum only. Examples are; a thrown ball, a fired bullet, a kicked ball, thrown javelin, etc.

Given that the ball was thrown vertically upward on the top of a skyscraper of height 61.9 m. So that the velocity can be determined by;

u = $\sqrt{\frac{2H}{g} }$

Where: u is the velocity of the object, H is the height and g is the gravitational force on the object. Given that: H = 61.9 m and g = 10 m/ $s^{2}$ , then;

u = $\sqrt{\frac{2*61.9}{10} }$

= $\sqrt{\frac{123.8}{10} }$

u = 3.5185

The velocity of the ball is 3.52 m/s.

3 0

4 years ago