The solution for this problem is:
r = [(2.90 + 0.0900t²) i - 0.0150t³ j] m/s²
this is for t in seconds and r in meters
v = dr/dt = [0.180t i - 0.0450t² j] m/s²
tan(-36.0º) = -0.0450t² / 0.180t
0.7265 = 0.25t
t = 2.91 s is the velocity vector of the insect
Before the engines fail , the rocket's horizontal and vertical position in the air are
and its velocity vector has components
After , its position is
and the rocket's velocity vector has horizontal and vertical components
After the engine failure , the rocket is in freefall and its position is given by
and its velocity vector's components are
where we take .
a. The maximum altitude occurs at the point during which :
At this point, the rocket has an altitude of
b. The rocket will eventually fall to the ground at some point after its engines fail. We solve for , then add 3 seconds to this time:
So the rocket stays in the air for a total of .
c. After the engine failure, the rocket traveled for about 34.6 seconds, so we evalute for this time :
Because its expose to the wires inside that could electrify you.
A) leaving a copper penny in vinegar until it turns green
Answer:10.4 times of initial velocity
Explanation:
Given
Diameter reduced by 69 %
it approaches with velocity
suppose its velocity is v during blocked passage
suppose d is the initial diameter and diameter is
As flow is constant